Question
If ∫dxx√1−x3=aln(√1−x3+b−√1−x3+1)+k, then
Answer: Option B
:
B
I=∫dxx√1−x3Put1−x3=t23x2dx=−2tdtI=−23∫dt(1−t2)=−13∫(11−t+11+t)dt.=−13log1+t1−t+c=−13log1+√1−x31−√1−x3+c.
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:
B
I=∫dxx√1−x3Put1−x3=t23x2dx=−2tdtI=−23∫dt(1−t2)=−13∫(11−t+11+t)dt.=−13log1+t1−t+c=−13log1+√1−x31−√1−x3+c.
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