Question
∫(2+sec x)sec x(1+2sec x)2dx
Answer: Option A
:
A
∫(2cosx+1)(2+cosx)2dx=∫(2+cosx)cosx+sin2x(2+cosx)2dx=∫cosx2+cosxdx−∫−sin2x(2+cosx)2dx=sinx2+cosx+c
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:
A
∫(2cosx+1)(2+cosx)2dx=∫(2+cosx)cosx+sin2x(2+cosx)2dx=∫cosx2+cosxdx−∫−sin2x(2+cosx)2dx=sinx2+cosx+c
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