Question
(2+x+x3)5=a0+a1x+.....+a15x15. find the value of a0+2a1+a2+2a3....+2a15
Answer: Option B
:
B
At x=1
a0+a1+.....+a15=45.............(1)
At x= -1
a0−a1+......−a15=0.................(2)
(1)-(2)=2a1+2a3.......2a15=45.........(3)
([(1)+(2)]2)=a0+a2...=452........(4)
(3)+(4)=a0+2a1+a2+2a3....+2a15=45+[452]=1536.
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B
At x=1
a0+a1+.....+a15=45.............(1)
At x= -1
a0−a1+......−a15=0.................(2)
(1)-(2)=2a1+2a3.......2a15=45.........(3)
([(1)+(2)]2)=a0+a2...=452........(4)
(3)+(4)=a0+2a1+a2+2a3....+2a15=45+[452]=1536.
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