PQR is a right angled triangle with PQ=8, QR=6, QT as altitude. If a circle is drawn with QT as diameter, what is the area of the shaded region?
Options:
A .  π−24
B .  (π−2)(125)26
C .  (π−2)(125)22
D .  (π−4)(65)22
E .  5222
Answer: Option C : C Let PT=x, Then 82-x2 = 62 - (10-x)2; ⇒ x = 6.4 Thus QT = 82 - 6.42 = 4.8; ST=4.8√2; Area of square STUQ =(4.8√2)2; Area of circle: π (2.4)2; Area of the shaded region: 12(π(2.4)2−(4.8√2)2)=(π−2)(125)22
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