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Quantitative Aptitude

TRIANGLES MCQs

Total Questions : 83 | Page 5 of 9 pages
Question 41. The centroid of a triangle is G. If area of ΔABC = 72 sq. unit, then the area of ΔBGC is?
  1.    16 sq. units
  2.    24 sq. units
  3.    36 sq. units
  4.    48 sq. units
 Discuss Question
Answer: Option B. -> 24 sq. units
G is centroid
Area of ΔBGC = $$\frac{1}{3}$$ area of ΔABC
ΔBGC = $$\frac{1}{3}$$ × 72
ΔBGC = 24 sq. units
Question 42. Possible length of the sides of a triangle are:
  1.    2cm, 3cm, 6cm
  2.    3cm, 4cm, 5cm
  3.    2.5cm, 3.5cm, 6cm
  4.    4cm, 4cm, 9cm
 Discuss Question
Answer: Option B. -> 3cm, 4cm, 5cm
If triangle's side are a, b, c then must be:-
a + b > c
or a - b < c
only option (B) satisfy
3 + 4 > 5
7 > 5
Question 43. ABC is an isosceles triangle inscribed in a circle. If AB = AC = 12$$\sqrt 5 $$ and BC = 24 cm then radius of circle is:
  1.    10 cm
  2.    15 cm
  3.    12 cm
  4.    14 cm
 Discuss Question
Answer: Option B. -> 15 cm
$$\eqalign{
& {R_2} = \frac{{abc}}{{4\vartriangle }} \cr
& \vartriangle = \sqrt {S\left( {s - a} \right)\left( {s - b} \right)\left( {s - c} \right)} \cr} $$
$$ = \sqrt {12\left( {\sqrt 5 + 1} \right)\left( {12} \right) \times 12 \times 12\left( {\sqrt 5 - 1} \right)} $$
where a = 12$$\sqrt 5 $$ , b = 12$$\sqrt 5 $$  & c = 24
$$\eqalign{
& S = \frac{{a + b + c}}{2} \cr
& S = \frac{{24\sqrt 5 + 24}}{2} \cr
& S = 12\left( {\sqrt 5 + 1} \right) \cr
& {R_2} = \frac{{12\sqrt 5 \times 12\sqrt 5 \times 24}}{{4 \times 12 \times 12 \times 2}} \cr
& {R_2} = \frac{{30}}{2} \cr
& {R_2} = 15\,{\text{cm}} \cr} $$
Question 44. ABC is an equilateral triangle and CD is the internal bisector of ∠C. If DC is produced to E such that AC = CE, then ∠CAE is equal to
  1.    45°
  2.    75°
  3.    30°
  4.    15°
 Discuss Question
Answer: Option D. -> 15°
According to question,
Given : ABC is an equilateral triangle CD is the angle bisector of ∠C
AC = CE
∴ ∠CAE = ∠CEA
   ∠ACD = 30°
∴ ∠ECA = 180° - 30°
   ∠ECA = 150°
In ΔCAE
   ∠CAE + ∠CEA + ∠ECA = 180°
∴ 2∠CAE = 180° - 150°
   2∠CAE = 30°
   ∠CAE = 15°
Question 45. In triangle ABC, ∠BAC = 75°, ∠ABC = 45°, $$\overline {BC} $$ is produced to D. If ∠ACD = x°, then $$\frac{x}{3}$$% of 60° is
  1.    30°
  2.    48°
  3.    15°
  4.    24°
 Discuss Question
Answer: Option D. -> 24°
According to question,
Given : ∠A = 75°,       ∠B = 45°
∴ ∠ACD = ∠A + ∠B
x° = ∠ACD = 120°
Now, $$\frac{x}{3}$$% of 60° is
= $$\frac{{120}}{3}$$ % of 60°
= 40% of 60°
= $$\frac{{40}}{{100}}$$ × 60°
= 24°
Question 46. In ΔABC and ΔDEF, AB = DE and BC = EF, then one can infer that ΔABC ≅ ΔDEF, when
  1.    ∠BAC = ∠EFD
  2.    ∠ACB = ∠EDF
  3.    ∠ABC = 2∠DEF
  4.    ∠ABC = ∠DEF
 Discuss Question
Answer: Option D. -> ∠ABC = ∠DEF
According to question,
∠ABC = ∠DEF
Note : Two triangles are congruent if two sides and the included angle of one triangle are equal to the corresponding sides and the included angles of the other triangle (SAS criterion).
Question 47. If each angle of a triangle is less than the sum of the other two, then the triangle is
  1.    Obtuse angled
  2.    Acute or equilateral
  3.    Acute angled
  4.    Equilateral
 Discuss Question
Answer: Option B. -> Acute or equilateral
According to question,
In equilateral triangle
∠A + ∠B > ∠C
60° + 60° > 60°
120° > 60°
In acute angle triangle
∠P + ∠Q > ∠R
60° + 40° > 80°
100° > 80°
Question 48. The angles of a triangle are in the ratio 2 : 3 : 7. The measure of the smallest angle is :
  1.    30°
  2.    60°
  3.    45°
  4.    90°
 Discuss Question
Answer: Option A. -> 30°
According to question,
Let angles are 2x, 3x and 7x
∠A + ∠B + ∠C = 180°
2x + 3x + 7x = 180°
12x = 180°
x = 15°
∴ Smallest angle is = 2 × 15° = 30°
Question 49. If angle bisector of a triangle bisects the opposite side, then what type of triangle is it?
  1.    Right angled
  2.    Equilateral
  3.    Isosceles and equilateral
  4.    Isosceles
 Discuss Question
Answer: Option C. -> Isosceles and equilateral
According to question,
AB = AC
BD = DC
The triangle will be isosceles and equilateral triangle
Question 50. If the sides of a right angled triangle are three consecutive integers, then the length of the smallest side is
  1.    3 units
  2.    2 units
  3.    4 units
  4.    5 units
 Discuss Question
Answer: Option A. -> 3 units
According to question,
ABC is a right angle triangle
By using Pythagoras theorem
AC2 = BC2 + AB2
52 = 32 + 42
25 = 9 + 16
25 = 25 (satisfied)
∴ Smallest length of right angle triangle is 3 units

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