Quantitative Aptitude
SURDS AND INDICES MCQs
Surds & Indices, Indices And Surds, Power
`(2^(n + 4) - 2 xx 2^n)/(2 xx 2^((n + 3))) + 2^ -3 ` = `(2^(n + 4) - 2^(n + 1))/(2^(n + 4)) + 1/2^3`
= `(2^(n + 1) (2^3 - 1))/(2^(n + 4)) + 1/2^3`
= `(2^(n + 1) xx 7)/(2^(n + 1) xx 2^3) + 1/2^3 ` = `(7/8 + 1/8)` = `8/8` = 1.
`3^x - 3^(x - 1) = 18 ` `hArr 3^(x - 1) (3 - 1) = 18 hArr 3^(x - 1) = 9 = 3^2 hArr x - 1 = 2 hArr x = 3`
`:.` ` x^x = 3^3 = 27`
`2^(n - 1) + 2^(n + 1) = 320 hArr 2^(n - 1) (1 + 2^2) = 320 hArr 5 xx 2^(n - 1) = 320`
`hArr 2^(n - 1) = 320/5= 64 = 2^6 hArr n- 1 = 6 hArr n= 7`
`2^(n + 4) - 2^(n + 2) = 3 hArr 2^(n + 2) (2^2 - 1) = 3 hArr 2^(n + 2) = 1 = 2^0 hArr n + 2 = 0 hArr n = - 2.`
`(9^n xx 3^5 xx (27)^3)/(3 xx (81)^4)` = 27 `hArr ((3^2)^n xx 3^5 xx (3^3)^3)/(3 xx (3^4)^4) = 3^3`
`hArr (3^(2n) xx 3^5 xx 3^((3xx3)))/(3 xx 3^(4 xx 4)) = 3^3 hArr (3^(2n + 5 + 9))/(3 xx 3^16) = 3^3`
`hArr (3^(2n + 14))/(3^17) = 3^3 hArr 3^(2n + 14 - 17) = 3^3`
`hArr 3^(2n - 3) = 3^3 hArr 2n - 3 = 3 hArr 2n = 6 hArr n` = 3.
`(sqrt(3))^5 xx 9^2 = 3^n xx 3sqrt(3)` `hArr (3^(1/2))^5 xx (3^3)^3 = 3^n xx 3 xx 3^(1/2)`
`hArr 3^((1/2 xx 5)) xx 3^(2 xx 2) = 3^((n + 1 + 1/2)) hArr 3^((5/2+ 4)) = 3^((n + 3/2))`
`hArr n + 3/2 = 13/2 hArr n = (13/2 - 3/2) = 10/2 = 5.`
`sqrt(2^n) = 64 hArr (2^n)^(1/2) = 2^6 hArr 2^(n/2) = 2^6 hArr n/2 = 6 hArr n = 12`.
`5sqrt(5) xx 5^3 -: 5^(-3/2)` = `5^(a + 2)` `hArr` `(5 xx 5^(1/2) xx 5^3)/(5^(- 3/2))` = `5^(a + 2)`
`hArr 5^((1 + 1/2 + 3 + 3/2)) = 5^(a + 2) hArr 5^6 = 5^(a + 2) hArr a + 2 = 6 hArr a = 4`.
`5^a` = 3125 `hArr 5^a = 5^5 hArr a = 5`
`:.` `5^(a -3) = 5^(5 - 3)= 5^2 `= 25.
`2^(2n - 1) = 1/8^(n - 3)` `hArr` `2^(2n - 1)` = `1/(2^3)^(n - 3)` = `(1)/2^(3(n - 3))` = `1/2^(3n - 9)`= `2^(9 - 3n)`
`hArr 2n - 1 = 9 - 3n hArr 5n =10 hArr n = 2`