Question
IIf `(sqrt(3))^5 xx 9^2 = 3^n xx 3sqrt(3)`, then the value of n is :
Answer: Option D
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`(sqrt(3))^5 xx 9^2 = 3^n xx 3sqrt(3)` `hArr (3^(1/2))^5 xx (3^3)^3 = 3^n xx 3 xx 3^(1/2)`
`hArr 3^((1/2 xx 5)) xx 3^(2 xx 2) = 3^((n + 1 + 1/2)) hArr 3^((5/2+ 4)) = 3^((n + 3/2))`
`hArr n + 3/2 = 13/2 hArr n = (13/2 - 3/2) = 10/2 = 5.`
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