10th Grade > Mathematics
STATISTICS MCQs
Total Questions : 60
| Page 3 of 6 pages
Answer: Option C. -> 82
:
C
The number of atheletes who completed the race in less than 14.6
= 2 + 4 + 5 + 71
= 82
:
C
The number of atheletes who completed the race in less than 14.6
= 2 + 4 + 5 + 71
= 82
Answer: Option A. -> l+(n2−cff ) ×h
:
A
The median for grouped data is formed by l+(n2−cff ) ×h.
Where l is lower class limit of median class.
n is total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
:
A
The median for grouped data is formed by l+(n2−cff ) ×h.
Where l is lower class limit of median class.
n is total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
Answer: Option A. -> xi−A
:
A
The deviation is di=xi−A
:
A
The deviation is di=xi−A
Answer: Option B. -> 22.86
:
B
Using, Mode = l+f1−f02f1−f0−f2×h
where,
Maximum class frequency, f1=8
The class corresponding to the frequency =20−40
Lower limit of the modal class, l=20
Frequency of class preceding the modal class, f0=7
Frequency of class succeeding the modal class, f2=2
Now,Mode=20+8−716−7−2×20
Mode=20+17×20
∴Mode=22.86
:
B
Using, Mode = l+f1−f02f1−f0−f2×h
where,
Maximum class frequency, f1=8
The class corresponding to the frequency =20−40
Lower limit of the modal class, l=20
Frequency of class preceding the modal class, f0=7
Frequency of class succeeding the modal class, f2=2
Now,Mode=20+8−716−7−2×20
Mode=20+17×20
∴Mode=22.86
Answer: Option B. -> Mode =3 Median - 2 Mean
:
B
The empirical relationship between Median, Mode and Mean is Mode = 3 Median - 2 Mean
:
B
The empirical relationship between Median, Mode and Mean is Mode = 3 Median - 2 Mean
Answer: Option A. -> ∑fixi∑fi
:
A
For grouped data, using the direct method first, we find the sum of the values of all the observations after multiplying them with their respective frequencies. Then we divide this result by the total number of observations (sum of all frequencies).
:
A
For grouped data, using the direct method first, we find the sum of the values of all the observations after multiplying them with their respective frequencies. Then we divide this result by the total number of observations (sum of all frequencies).
:
The method in question is the step-deviation method.
Answer: Option A. -> 145 - 150
:
A
The given table can be written as:
Height(in cm)Lessthan140Lessthan 145Less than 150Lessthan155Lessthan 160Less than 165No. of girls41129404651
Height(in cm)Less than 140140−145145−150150−155155−160160−165Cumulative Frequency41129404651
n = 51
∴n2=512
= 25.5
Since there are a total of 51 observations, the median class is the one whose cumulative frequency is closest to and greater than 25.5. The cumulative frequency for the class '145 - 150' is 29 which is greater than 25.5. The median class is '140 - 145'. Thus, the class interval '145 - 150' is the required answer.
:
A
The given table can be written as:
Height(in cm)Lessthan140Lessthan 145Less than 150Lessthan155Lessthan 160Less than 165No. of girls41129404651
Height(in cm)Less than 140140−145145−150150−155155−160160−165Cumulative Frequency41129404651
n = 51
∴n2=512
= 25.5
Since there are a total of 51 observations, the median class is the one whose cumulative frequency is closest to and greater than 25.5. The cumulative frequency for the class '145 - 150' is 29 which is greater than 25.5. The median class is '140 - 145'. Thus, the class interval '145 - 150' is the required answer.
Answer: Option A. -> 102.86
:
A
ClassIntervalFrequencyCumulativeFrequency60−702270−803580−9051090−1001626100−1101440110−1201353120−130760
n2=30.
So, the median class is the one whose cumulative frequency is closest to and greater than 30.
∴ the median class is 100-110
Median=l+(n2−cff)×h
Where l is lower class limit of median class.
n is total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
⟹Median=100+30−2614×10
∴Median=102.86
:
A
ClassIntervalFrequencyCumulativeFrequency60−702270−803580−9051090−1001626100−1101440110−1201353120−130760
n2=30.
So, the median class is the one whose cumulative frequency is closest to and greater than 30.
∴ the median class is 100-110
Median=l+(n2−cff)×h
Where l is lower class limit of median class.
n is total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
⟹Median=100+30−2614×10
∴Median=102.86
Answer: Option A. -> True
:
A
¯x=A+∑fidi∑fi
In the formula, the A stands for the assumed mean.
:
A
¯x=A+∑fidi∑fi
In the formula, the A stands for the assumed mean.
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