The reciprocal of any non-zero number 'a' is $\frac{1}{a}$.
​​​​​​The reciprocal of '-10' = $\frac{1}{(-10)}=-0.1$

In the fractions $\frac{1}{3}$ and  $\frac{5}{3}$, the denominators are same.
So, considering numerator values, we can find the required rational number.
4 lies between 1 and 5.
So, keep 4 in the numerator and keep the same denominator as it is.
The required rational number is $\frac{4}{3}$.

$\frac{-12}{x}=3$
$\Rightarrow \frac{-12}{3}=x$
Or
$x=-4$

Let the rational number be $x$.

$\frac{22}{7}÷x$  = $\frac{-11}{14}$ (given)

$\Rightarrow \frac{22}{7}=x\times \frac{-11}{14}$
$\Rightarrow \frac{22}{7}÷\frac{-11}{14}=x$
$\Rightarrow \frac{22}{7}\times \frac{14}{-11}=x$

$\Rightarrow x=-4$
Therefore, $\frac{22}{7}$ should be divided by -4 to get $\frac{-11}{14}$.

Let's first evaluate LHS.

$\left(\frac{59}{13}\right)\times \frac{1}{52}=\frac{59}{676}$

Now, RHS
$59\times \left(\frac{52}{13}\right)$

$=\frac{3068}{13}$

We see that both LHS and RHS are not equal.

Natural numbers start from 1 and goes on as 2, 3, 4, ...

$\frac{3}{10}=0.3\text{and}\frac{7}{10}=0.7$
Thus, there are no natural numbers between 0.3 and 0.7.

There are only 4 natural numbers between 15 and 20 which are 16, 17, 18 and 19.

Zero is the additive identity for rational numbers, integers and whole numbers, as adding zero to these numbers does not affect its value.

$Eg:a+0=0+a=a.$

All real numbers can be represented on a number line and rational numbers are also real numbers. Thus rational numbers can also be represented on the number line.

Multiplication of any number with its reciprocal results in 1.
$\text{For example},\frac{2}{5}\times \frac{5}{2}=1$