Ratio And Proportion(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

RATIO AND PROPORTION MCQs

Ratio & Proportion, Ratio, Proportion

Total Questions : 895 | Page 88 of 90 pages

Question 871. X, Y and Z are quantities of the same kind such that X:Y=5:8 and Y:Z=4:7. Find X:Z.

32:35
67:56
5:14
5:7

Discuss Question

Answer: Option C. -> 5:14
X:Z=(X:Y)*(Y:Z) =(5:8)*(4:7) = (5/8)*(4/7) = 5/14

Question 872. Solve for x
2x:25 = 6:(x/3)

Discuss Question

Answer: Option B. -> 15
2X/25 = 6/(X/3) 2X/25 = 18/X 2X*X = 18*25 X² = 9*25 X=3*5 X=15

Question 873. A, B, C and D divide a sum of money among themselves in the ratio 7:4:3:2. If D gets Rs. 500 less than A, find the total amount.

Rs.100
Rs.700
Rs.1600
Rs.2000

Discuss Question

Answer: Option C. -> Rs.1600
LET THE AMOUNT BE DIVIDED INTO 7X,4X,3X AND 2X.
7X-2X = 500 5X=500 X = 100
TOTAL AMOUNT = 7X+4X+3X+2X = 16X = RS.1600

Question 874. Two natural numbers whose sum is 72 cannot be in the ratio:

Discuss Question

Answer: Option D. -> 3:4
72 SHOULD BE DIVISIBLE BY ADDITION OF THE ABOVE RATIO.
USING TRIAL AND ERROR METHOD
FOR (A): – 1+2 = 3, 72 IS DIVISIBLE BY 3
FOR (B): – 3+5 = 8, 72 IS DIVISIBLE BY 8
FOR (A): – 1+3 = 4, 72 IS DIVISIBLE BY 4
FOR (A): – 3+4 = 7, 72 IS NOT DIVISIBLE BY 7
THEREFORE, THE ANSWER IS OPTION (D)

Question 875. A journey of 750 km was covered partly by car(x km) and partly by train(y km). If the distance travelled by train was 150 km more than the distance travelled by car, find x:y.

Discuss Question

Answer: Option A. -> 2:3
X+Y = 750 Y-X = 150 SOLVING,
Y = 450
X = 300 X:Y = 300:450 = 2:3

Question 876. According to a recipe, 400 grams of flour should be mixed with 500 grams of sugar to bake cookies. If I have only 300 grams of flour, how much sugar should I mix to maintain the same proportion?

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Answer: Option C. -> 375
FLOUR AND SUGAR HAVE TO MIXED IN THE RATIO 4:5 4:5::300:X 4X=1500 X=375 375 GRAMS OF SUGAR SHOULD BE MIXED.

Question 877. Two kinds of rice, 1st costs Rs.13 per kg and 2nd costs Rs.19 per kg are mixed together. Find the ratio in which the 2 types are mixed so that the mixture costs Rs.14.2 per kg?

Discuss Question

Answer: Option B. -> 4:1
LET THE TOTAL QUANTITY OF MIXTURE BE 1. IF QUANTITY OF 1ST TYPE IS X THEN QUANTITY OF THE 2ND TYPE WILL BE (1-X)
THEREFORE, 13X + 19(1-X) = 14.2
13X -19X + 19 = 14.2
4.8 = 6X
X = 0.8 ; (1-X) = 0.2
THEREFORE, THE RATIO IS 0.8 : 0.2 = 4:1

Question 878. P is 50% more than q. Find the ratio of p to q.

Discuss Question

Answer: Option A. -> 3:2
P = Q+(50/100)Q = 1.5Q P:Q = 1.5Q:Q = 1.5:1 = 3:2

Question 879. The sum of squares of three numbers is 280. If the numbers are in the ratio 3:5:6, find the greatest number.

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Answer: Option C. -> 12
LET THE NUMBERS BE 3X,5X AND 6X. (3X)²+(5X)²+(6X)²=280 9X²+25X²+36X²=280 70X²=280 X²=4 X=2 THE GREATEST NUMBER IS 6X=12.

Question 880. A:B=2:3, B:C=3:4, A:D=4:5. Find C:D.

Discuss Question

Answer: Option D. -> 8:5
A:C=(A:B)*(B:C) =(2/3)*(3/4)= 1/2 C:D=(C:A)*(A:D) =(2)*(4/5) = 8:5