Ratio And Proportion(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

RATIO AND PROPORTION MCQs

Ratio & Proportion, Ratio, Proportion

Total Questions : 895 | Page 87 of 90 pages

Question 861. The perimeter of a triangle is 81 cm. If the sides are in the ratio 4:3:2, find the length of the largest side.

45 cm
40 cm
36 cm
27 cm

Discuss Question

Answer: Option C. -> 36 cm
LET THE THREE SIDES BE 4X,3X AND 2X. 4X+3X+2X = 81 9X = 81 X = 9 LENGTH OF THE LARGEST SIDE
= 4X = 36 CM

Question 862. In what ratio should the profit of Rs.8000 be divided if X starts a business with an investment of Rs. 20000, Y invests Rs.7500 for 4 months and Z invests Rs.15000 after 3 months from the start of the business.

16 : 2 : 3
8 : 3 : 6
16 : 2 : 9
6 : 9 : 1

Discuss Question

Answer: Option C. -> 16 : 2 : 9
LET THE PROFIT OF X BE P1, THAT OF Y BE P2 AND OF Z BE P3.
P1:P2:P3 = 20000*12 : 7500*4 : 15000*9 = 240 : 30 : 135 = 80 : 10 : 45
= 16 : 2 : 9

Question 863. A class has 90 students. If the ratio of boys and girls is 7:8, find the number of boys in the class.

Discuss Question

Answer: Option B. -> 42
7X+8X=90 15X=90 X=6 NUMBER OF BOYS=7X=42

Question 864. Divide Rs.2000 into two shares in the ratio 3:2.

Rs.1200,Rs.800
Rs.800,Rs.1200
Rs.1500,Rs.500
Rs.1100, Rs.900

Discuss Question

Answer: Option A. -> Rs.1200,Rs.800
3X+2X=2000 5X=2000 X=400 3X=1200 2X=800

Question 865. A bag contains 1 rupee, 2 rupee and 5 rupee coins amounting to Rs.264. If the ratio of the number of these coins is 3:5:4, find the number of 1 rupee coins.

Discuss Question

Answer: Option C. -> 24
LET THE NUMBER OF 1 RUPEE, 2 RUPEE AND 5 RUPEE COINS BE 3X, 5X AND 4X. (1*3X)+(2*5X)+(5*4X)=264 3X+10X+20X=264 33X=264 X=8 NO. OF 1 RUPEE COINS
= 3X = 24

Question 866. In a partnership for a business, Changaz invests Rs.6000 for complete year & Nasir invests Rs.3000 for 6 months. What is Nasir’s share if they earn Rs.240 as profit?

Discuss Question

Answer: Option D. -> 48
IF A INVESTS AMOUNT C1 FOR T1 TIME AND HIS SHARE OF PROFIT IS P1, AND B INVESTS AMOUNT C2 FOR T2 TIME AND HIS SHARE OF PROFIT IS P2, THEN, C1 * T1 / C2 * T2 = P1/P2
IF P IS THE NASIR’S SHARE OF PROFIT, THEN CHANGAZ GETS (240 – P)
THEREFORE, 6000 * 12 / 3000 * 6 = (240 – P) / P = 72/ 18 = 4
4P = (240 – P)
5P = 240
P = 48

Question 867. If x% of 200=y% of 250, find y:x.

Discuss Question

Answer: Option D. -> 4:5
(X/100)*200 = (Y/100)*250 Y/X = 20/25 = 4/5 Y:X=4:5

Question 868. The ratio of two numbers is 5:9. If each number is decreased by 5, the ratio becomes 5:11. Find the numbers.

30, 19
21, 37
15, 34
15, 27

Discuss Question

Answer: Option D. -> 15, 27
LET THE TWO NUMBERS BE 5X AND 9X.
(5X-5)/(9X-5) = 5:11
(5X-5)*11 = (9X-5)*5
55X – 55 = 45X – 25
10X = 30
X = 3
THEREFORE, THE NUMBERS ARE 15 AND 27.

Question 869. The third proportional to 3.5, 5.6 is:___________?