Quantitative Aptitude
PROFIT AND LOSS MCQs
Profit & Loss
Total Questions : 2016
| Page 197 of 202 pages
Answer: Option E. -> None of these
GIVEN THAT, COST PRICE OF 50 ARTICLE IS EQUAL TO SELLING PRICE OF 40 ARTICLES.
LET COST PRICE OF ONE ARTICLE = RS. 1
SELLING PRICE OF 40 ARTICLES = RS. 50
BUT COST PRICE OF 40 ARTICLES = RS. 40
THEREFORE, THE TRADER MADE PROFIT.PERCENTAGE OF PROFIT = 10/40 * 100 = 25%
GIVEN THAT, COST PRICE OF 50 ARTICLE IS EQUAL TO SELLING PRICE OF 40 ARTICLES.
LET COST PRICE OF ONE ARTICLE = RS. 1
SELLING PRICE OF 40 ARTICLES = RS. 50
BUT COST PRICE OF 40 ARTICLES = RS. 40
THEREFORE, THE TRADER MADE PROFIT.PERCENTAGE OF PROFIT = 10/40 * 100 = 25%
Answer: Option A. -> 1.44% loss
SP OF EACH CAR IS RS. 325475, HE GAINS 12% ON FIRST CAR AND LOSSES 12% ON SECOND CAR.
IN THIS CASE, THERE WILL BE LOSS AND PERCENTAGE OF LOSS IS GIVEN BY = [(PROFIT%)(LOSS%)]/100 = (12)(12)/100 % = 1.44%
SP OF EACH CAR IS RS. 325475, HE GAINS 12% ON FIRST CAR AND LOSSES 12% ON SECOND CAR.
IN THIS CASE, THERE WILL BE LOSS AND PERCENTAGE OF LOSS IS GIVEN BY = [(PROFIT%)(LOSS%)]/100 = (12)(12)/100 % = 1.44%
Answer: Option C. -> Rs. 189
CP PER KG OF MIXTURE = [24(150) + 36(125)]/(24 + 36) = RS. 135
SP = CP[(100 + PROFIT%)/100]
= 135 * [(100 + 40)/100] = RS. 189.
CP PER KG OF MIXTURE = [24(150) + 36(125)]/(24 + 36) = RS. 135
SP = CP[(100 + PROFIT%)/100]
= 135 * [(100 + 40)/100] = RS. 189.
Answer: Option C. -> Rs. 1500
LET THE COST PRICE OF AN ARTICLE BE RS. X.
(19% OF X) – (12% OF X) = 105
19X/100 – 12X/100 = 105 => 7X = 105 * 100
=> X = 1500
COST PRICE = RS. 1500
LET THE COST PRICE OF AN ARTICLE BE RS. X.
(19% OF X) – (12% OF X) = 105
19X/100 – 12X/100 = 105 => 7X = 105 * 100
=> X = 1500
COST PRICE = RS. 1500
Answer: Option C. -> 40%
THE TOTAL CP = RS. 16000 + RS. 6250 = RS. 22250 AND SP = RS. 31150
PROFIT(%) = (31150 – 22250)/22250 * 100 = 40%
THE TOTAL CP = RS. 16000 + RS. 6250 = RS. 22250 AND SP = RS. 31150
PROFIT(%) = (31150 – 22250)/22250 * 100 = 40%
Answer: Option B. -> Rs. 144
GIVEN THAT SP = RS. 102 AND LOSS = 15%
CP = [100(SP)]/(100 – L%) = (100 * 102)/85 = 20 * 6 = RS. 120.
TO GET 20% PROFIT, NEW SP = [(100 + P%)CP]/100 = (120 * 120)/100 = RS. 144
GIVEN THAT SP = RS. 102 AND LOSS = 15%
CP = [100(SP)]/(100 – L%) = (100 * 102)/85 = 20 * 6 = RS. 120.
TO GET 20% PROFIT, NEW SP = [(100 + P%)CP]/100 = (120 * 120)/100 = RS. 144
Answer: Option C. -> 18%
TOTAL CP = RS. 42000 + RS. 13000 = RS. 55000 AND SP = RS. 64900
PROFIT(%) = (64900 – 55000)/55000 * 100 = 18%
TOTAL CP = RS. 42000 + RS. 13000 = RS. 55000 AND SP = RS. 64900
PROFIT(%) = (64900 – 55000)/55000 * 100 = 18%
Answer: Option C. -> Rs. 90
SP OF 1M OF CLOTH = 8925/85 = RS. 105
CP OF 1M OF CLOTH = SP OF 1M OF CLOTH – PROFIT ON 1M OF CLOTH
= RS. 105 – RS. 15 = RS. 90.
SP OF 1M OF CLOTH = 8925/85 = RS. 105
CP OF 1M OF CLOTH = SP OF 1M OF CLOTH – PROFIT ON 1M OF CLOTH
= RS. 105 – RS. 15 = RS. 90.
Answer: Option D. -> Rs. 6725
CP = SP * (100/(100 + PROFIT%))
= 8339(100/124) = RS. 6725.
CP = SP * (100/(100 + PROFIT%))
= 8339(100/124) = RS. 6725.
Answer: Option B. -> 833 1/3 grams
IF THE COST PRICE IS RS.100, THEN TO GET A PROFIT OF 20%, THE SELLING PRICE SHOULD BE RS.120.
IF 120KG ARE TO BE SOLD, AND THE DEALER GIVES ONLY 100KG, TO GET A PROFIT OF 20%.
HOW MANY GRAMS HE HAS TO GIVE INSTEAD OF ONE KILOGRAM(1000 GM).
120 GM —— 100 GM
1000 GM —— ?
(1000 * 100)/120 = 2500/3 = 833 1/3 GRAMS.
IF THE COST PRICE IS RS.100, THEN TO GET A PROFIT OF 20%, THE SELLING PRICE SHOULD BE RS.120.
IF 120KG ARE TO BE SOLD, AND THE DEALER GIVES ONLY 100KG, TO GET A PROFIT OF 20%.
HOW MANY GRAMS HE HAS TO GIVE INSTEAD OF ONE KILOGRAM(1000 GM).
120 GM —— 100 GM
1000 GM —— ?
(1000 * 100)/120 = 2500/3 = 833 1/3 GRAMS.