7th Grade > Mathematics
PRACTICAL GEOMETRY MCQs
Total Questions : 105
| Page 4 of 11 pages
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The condition to form a triangle is that sum of the lengths of two sides of a triangle must be greater than the third one.
Consider 3 cm , 7 cm and 14 cm ;
3 + 7≯ 14 cm
Similarily if we consider other combination 7 ,14 ,21 , 14 + 21≯ 7
Hence no triangles can be formed.
Answer: Option A. -> True
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A
If two lines are parallel to each other, then the corresponding angles formed when a transversal passes through them are equal. Bythe converse of the previous statement, if the corresponding angles are equal, then the lines must be parallel. So, Pavan's conclusion is true.
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A
If two lines are parallel to each other, then the corresponding angles formed when a transversal passes through them are equal. Bythe converse of the previous statement, if the corresponding angles are equal, then the lines must be parallel. So, Pavan's conclusion is true.
Answer: Option C. -> Statement 2 is correct but statement 1 is incorrect.
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C
Statement 2 iscorrect whilestatement 1 is incorrect.
Reason:-If the lines are perpendicular to each other, then the pair of vertically opposite angles are also supplementary.
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C
Statement 2 iscorrect whilestatement 1 is incorrect.
Reason:-If the lines are perpendicular to each other, then the pair of vertically opposite angles are also supplementary.
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When a line segment is perpendicular to another line segment then angle between them is 90∘.
Answer: Option B. -> False
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B
Parallel lines never intersect. Parallel linesarelinesin a plane which do not meet, that is, twolinesin a plane that do not intersect or touch each other at any point are said to beparallel.
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B
Parallel lines never intersect. Parallel linesarelinesin a plane which do not meet, that is, twolinesin a plane that do not intersect or touch each other at any point are said to beparallel.
Question 36. Pavan tried to draw a line parallel to a given line, 'l'. Few steps are shown below. What will be the next step?
Step 1: Mark a point A, not on the line 'l'.
Step 2: Mark point B on line 'l'.
Step 3: Draw line segment joining points A and B.
Step 4: Draw an arc with B as the centre, such that it intersects line 'l' at D and AB at E.
Step 1: Mark a point A, not on the line 'l'.
Step 2: Mark point B on line 'l'.
Step 3: Draw line segment joining points A and B.
Step 4: Draw an arc with B as the centre, such that it intersects line 'l' at D and AB at E.
Answer: Option A. -> Draw another arc with the same radius and A as the centre, such that it intersects AB at F
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A
Following are the steps to draw aline parallel to a given line:
Step 1: Mark a point A, not on the line 'l'.
Step 2: Mark point B on line 'l'.
Step 3: Draw line segmentjoining points A and B.
Step 4: Draw an arc with B as the centre, such that it intersects line 'l' at D and AB at E.
Step 5: Draw another arc with the same radius and A as the centre, such that it intersectsABat F.
Step 6: Draw another arc with F as the centre and distance DE as the radius.
Step 7:Mark the point of intersections of this arc and the previous arc as G.
Step 8: Draw line 'm' passing through points A and G.
Line 'm' is the required parallel line.
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A
Following are the steps to draw aline parallel to a given line:
Step 1: Mark a point A, not on the line 'l'.
Step 2: Mark point B on line 'l'.
Step 3: Draw line segmentjoining points A and B.
Step 4: Draw an arc with B as the centre, such that it intersects line 'l' at D and AB at E.
Step 5: Draw another arc with the same radius and A as the centre, such that it intersectsABat F.
Step 6: Draw another arc with F as the centre and distance DE as the radius.
Step 7:Mark the point of intersections of this arc and the previous arc as G.
Step 8: Draw line 'm' passing through points A and G.
Line 'm' is the required parallel line.
Answer: Option A. -> right-angled
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A
Let us construct the required triangle as follows:
Step 1:
Draw the base line XYof the length 3cm.
Step 2:
Use your compass to make an arcwith centre at point Yand the radius 4cm.
Step 3:
Use your compass to make a circle with centre at point Xand the radius 5cm.
Step 4:
The point of intersection between the arcs is named as X.
The triangle is completed by joining all these three points.
Now, fromabove constructionwe see that the triangle formed is a right angle triangle.
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A
Let us construct the required triangle as follows:
Step 1:
Draw the base line XYof the length 3cm.
Step 2:
Use your compass to make an arcwith centre at point Yand the radius 4cm.
Step 3:
Use your compass to make a circle with centre at point Xand the radius 5cm.
Step 4:
The point of intersection between the arcs is named as X.
The triangle is completed by joining all these three points.
Now, fromabove constructionwe see that the triangle formed is a right angle triangle.
Answer: Option B. -> False
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B
We are given two angles and one side. So, data is sufficient and the triangle can be drawn.
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B
We are given two angles and one side. So, data is sufficient and the triangle can be drawn.
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Each corner has three mutually perpendicular linesand a cuboid has 8 corners. Hence, the total number of right angles in a cubical room is 8×3=24.
Question 40. (a) Draw a line l. Draw a perpendicular on l at any point. On this perpendicular, choose a point X, 4 cm away from l. Through X, draw a line m parallel to l.
(b) Line l and m are parallel to each other. A transversal intersects them at points A and B.
i) An arc of suitable measure is taken from B cutting ‘l’ at D and transversal at M (as shown in the figure).
ii) Now, with the same radius and A as the centre an arc FG is drawn (as shown in the figure).
What is the relation between the length of arc DM and arc FG?
[4 MARKS]
(b) Line l and m are parallel to each other. A transversal intersects them at points A and B.
i) An arc of suitable measure is taken from B cutting ‘l’ at D and transversal at M (as shown in the figure).
ii) Now, with the same radius and A as the centre an arc FG is drawn (as shown in the figure).
What is the relation between the length of arc DM and arc FG?
[4 MARKS]
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Each part: 2 Marks
(a) To construct: A line parallel to given line when the perpendicular line is also given.
Draw a line l and take a point P on it.
At point P, draw a perpendicular line n.
Take PX = 4 cm on line n.
At point X, again draw the line m.
(b)Since both the angles are alternate interior angles, they will be equal to each other. Also, since both arcs are drawn with the same radius, they are part of two equal circles. This means that they both have same shape and size. Thus, the two arcs DM and FG are congruent which makestheir lengthsequal.