:
If he was able to draw a triangle with two sides and an angle which is not included, then the triangle should be a right angled triangle.

:
As stated in question AB||CD and if $\angle CFE$ = ${90}^{\circ }$, so $\angle FEB$ is an alternate angle to $\angle CFE$ which should be equal.
So, $\angle CFE={90}^{\circ }$.

Answer: Option C. -> 3 and 1
:
C
Steps for drawing a line parallel to a given line:
Step 1: Mark a point A, not on the line 'l'.
Step 2: Mark point B on line 'l'.
Step 3: Draw line segmentjoining points A and B.
Step 4: Draw an arc with B as the centre, such that it intersects line 'l' at D and AB at E.
Step 5: Draw another arc with the same radius and A as the centre, such that it intersectsABat F.
Step 6: Draw another arc with F as the centre and distance DE as the radius.
Step 7:Mark the point of intersections of this arc and the previous arc as G.
Step 8: Draw line 'm' passing through points A and G.
No. of arcs drawn = $3$
No. of times the distance between compass tip and pencip tip is changed = $1$

Answer: Option B. -> False
:
B
We can construct a line parallel to a given lineby using alternate angles as well as corresponding angles concept. So, the statement is false.
If two parallel lines are intersected by a transversal:

(i) alternate interior angles are equal i.e., $2=8and3=5$
(ii) alternate exterior angles are equal i.e., $1=7and4=6$
(iii) corresponding angles are equal i.e., $1=5,4=8,2=6and3=7$
(iv) co-interior angles are supplementary i.e., $2+5={180}^{\circ }and3+8={180}^{\circ }$
A line can be constructed parallel to a given line by making any of the above mentioned pairs of angles equal.

Answer: Option B. -> False
:
B
If two parallel lines are intersected by a transversal:

(i) alternate interior angles are equal i.e., $\angle$2=$\angle$8 and $\angle$3=$\angle$5
(ii) alternate exterior angles are equal i.e., $\angle$1=$\angle$7 and $\angle$4=$\angle$6
(iii) corresponding angles are equal i.e., $\angle$1=$\angle$5,$\angle$4=$\angle$8,$\angle$2=$\angle$6 and $\angle$3=$\angle$7
(iv) co-interior angles are supplementary i.e., $\angle$2 +$\angle$5= ${180}^{\circ }and\angle$3 +$\angle$8 =${180}^{\circ }$.
Hence, if the alternate angles are equal then the lines are parallel.

Answer: Option A. -> True
:
A
We can only draw one line parallel to a given line passing through a point that is not on the line.

:
When a line segment is perpendicular to another line segment then angle between them is${90}^o$.

Answer: Option D. -> Do not need anything else as the triangle can be constructed from the given data
:
D
If the lengths of the two sides enclosing the right angle in a right-angled triangle are given, we do not require any more data to draw the triangle.

Answer: Option A. -> True
:
A
If two lines are parallel then a line drawn parallel to the one of them will be parallel tothe other line too.

:
The sum of anytwo sides of a triangle is greaterthan the third side.
Here, $7cm+3cm=10cm$, which is less than $14cm$. So, a triangle can't be constructed.
Therefore, Akashwill not get the arcs intersecting at any point.