12th Grade > Chemistry
P BLOCK ELEMENTS MCQs
Total Questions : 30
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Answer: Option D. -> Boric anhydride
:
D
H3BO3100∘C−−−→HBO2160∘C−−−→H2B4O7+H2O↓2B2O3+H2O
:
D
H3BO3100∘C−−−→HBO2160∘C−−−→H2B4O7+H2O↓2B2O3+H2O
Answer: Option B. -> Ammonia
:
B
Serpeck's process involves -
Al2O3+3C+N2→2AlN+3COAlN+3H2O→Al(OH)3↓+NH32Al(OH)3Δ−→Al2O3+3H2O
:
B
Serpeck's process involves -
Al2O3+3C+N2→2AlN+3COAlN+3H2O→Al(OH)3↓+NH32Al(OH)3Δ−→Al2O3+3H2O
Answer: Option C. -> H3BO3
:
C
Na2B4O7+H2SO4+5H2O→Na2SO4+4H3BO3
:
C
Na2B4O7+H2SO4+5H2O→Na2SO4+4H3BO3
Answer: Option D. -> Formation of 2 mol each of [B(OH)4]− and B(OH)3, of which only[B(OH)4]− reacts with acid
:
D
Na2B4O7+7H2O→2B(OH)3+2Na[B(OH)4]
B(OH)3orH3BO3 is an acid and does not react with acid.
Hence Na[B(OH)4] reacts with acid.
:
D
Na2B4O7+7H2O→2B(OH)3+2Na[B(OH)4]
B(OH)3orH3BO3 is an acid and does not react with acid.
Hence Na[B(OH)4] reacts with acid.
Answer: Option C. -> It forms R2O3.
:
C
Group 13 elements belong to the boron family. The oxidation state of group 13 elements is either +1 or +3. All the group 13 elements are solids at room temperature. Valency of element R present in 13th group of the periodic table is 3. Hence it can form R2O3 when it reacts with oxygen.
:
C
Group 13 elements belong to the boron family. The oxidation state of group 13 elements is either +1 or +3. All the group 13 elements are solids at room temperature. Valency of element R present in 13th group of the periodic table is 3. Hence it can form R2O3 when it reacts with oxygen.
Answer: Option D. -> pp- pp back bonding
:
D
It is pp- pp bonding involving B and F atom responsible for the acidic nature of boron halides as BF3<BCl3<BBr3< BI3smaller atom shows more back bonding
:
D
It is pp- pp bonding involving B and F atom responsible for the acidic nature of boron halides as BF3<BCl3<BBr3< BI3smaller atom shows more back bonding
Answer: Option D. -> Cu(BO2)2
:
D
Compound (A) is - NaBO2
Compound (B) is - Na2B4O7
Compound (C) is - H3BO3
Compound (D) is - B2O3
Compound (E) is - Cu(BO2)2
:
D
Compound (A) is - NaBO2
Compound (B) is - Na2B4O7
Compound (C) is - H3BO3
Compound (D) is - B2O3
Compound (E) is - Cu(BO2)2
Answer: Option C. -> Poor shielding effect of d-electrons of Ga atoms
:
C
Due to poor shielding effect of d-electrons, nuclear attraction over valency electrons increases hence atomic size decreases
:
C
Due to poor shielding effect of d-electrons, nuclear attraction over valency electrons increases hence atomic size decreases
Answer: Option A. -> [BF6]3−
:
A
BF3−6does not exist because boron does not have vacant d-subshells
:
A
BF3−6does not exist because boron does not have vacant d-subshells