Numerical Ability Combined(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

NUMERICAL ABILITY COMBINED MCQs

Total Questions : 450 | Page 37 of 45 pages

Question 361. The average weight of 15 girls was recorded as 54 kgs. If the weight of the teacher was added the average increased by two kgs. What was the teacher's weight?

75 Kgs
95 Kgs
78 Kgs
86 Kgs
None of these

Discuss Question

Answer: Option D. -> 86 Kgs

Weight of the teacher = 54 + 2 * 6 = 86 kg

Question 362. Vikram scored 72 percent marks in five subjects together; viz; Hindi, Science, Maths, English and Sanskrit together, wherein the maximum marks of each subject were 100. How many marks did Vikram score in Science if he scored 80 marks in Hindi, 76 marks in Maths and 65 marks in English?

72
69
59
71
None of these

Discuss Question

Answer: Option B. -> 69

Total marks obtained by Vikram

= (500*72)/100 = 360

His marks in Science = 360-(80+70+76+65)

= 360-291 = 69

Question 363. The sum of 15% of a positive number and 10% of the same number is 70. What is twice of that number?

440
280
560
140
None of these

Discuss Question

Answer: Option C. -> 560

Let the number be x

âˆ´ (x * 25)/100 = 70

=> x = (70 * 100)/25 = 280

âˆ´ Required answer = 2 * 280 = 560

Question 364. The respective ratio between Pooja's, Prarthana's and Falguni's monthly income is 53:70:57:. If Prarthana's annual income is Rs.4,20,000, what is the sum of Pooja's and Falguni's annual incomes?(In some cases monthly income and in some cases annual income is used.)

Rs. 5, 92, 500
Rs. 6, 83, 500
Rs. 6, 60, 000
Rs. 7, 79, 200
None of these

Discuss Question

Answer: Option C. -> Rs. 6, 60, 000

Sum of Pooja's and Falguni's annual incomes

= Rs.((53+57)/70 * 420000)

= Rs. 660000

Question 365. Find the average of the following set of scores:

152. 635, 121, 423, 632, 744, 365, 253, 302

403
396
428
383
None of these

Discuss Question

Answer: Option A. -> 403

Required average

= (152+635+121+423+632+744+365+253+302)/9

= 3627/9 = 403

Question 366. Riya, Manasvi and Pintu start running around a circular stadium and complete one round in 24 seconds, 6 seconds and 14 seconds respectively. In how much time will they meet again at the starting point?

1 min. 32 seconds
4 min. 8 seconds
3 min. 25 seconds
2 min. 48. seconds
None of these

Discuss Question

Answer: Option D. -> 2 min. 48. seconds

Required time = LCM of 24, 6 and 14 seconds

= 168 seconds

= 2 minutes 48 seconds

Question 367. The perimeter of a square is one-fourth the perimeter of a rectangle. If the perimeter of the square is 44 cms and the length of the rectangle is 51 cms, what is the difference between the breadth of the rectangle and the side of the square?

30 cm
18 cm
26 cm
32 cm
None of these

Discuss Question

Answer: Option C. -> 26 cm

Perimeter of rectangle = 4 * 44

= 176 cm.

Width of rectangle

= (176/2) - 51 = 37 cm.

Side of square

= Perimeter/4 = 44/4 = 11 cm.

âˆ´ Required Difference = 37 - 11 = 26 cm

Question 368. On children's day sweets were to be equally distributed among 200 children, But on that particular day 40 children remained absent; hence each child got 2 sweets extra. How many sweets were distributed?

3000
1500
2000
1600
Cannot be determined

Discuss Question

Answer: Option D. -> 1600

Let the total number of sweets be x,

âˆ´ x/160 - x/200 = 2

=>(5x-4x)/800 = 2

=> x = 800 * 2

=> x = 1600

Question 369. A 240 meter long train crosses a platform twice its length in 2 minutes. What is the speed of the train ?

8 m/sec
4 m/sec
6 m/sec
Cannot be determined
None of these

Discuss Question

Answer: Option C. -> 6 m/sec

Speed of train = Length of (platform+train) / Time taken to crossing

= (480+240)/(2*60) m/sec

= 6 m/sec

Question 370. What is the difference between the compound interest and simple interest accured on an amount of Rx. 12,000 at the end of three years at the rate of 12%?

Rs. 539.136
Rs. 602.242
Rs. 495.248
Rs. 488.322
None of these

Discuss Question

Answer: Option A. -> Rs. 539.136

S.I = (Principal * Time * Rate)/100
= (12000 * 3 * 12) / 100 = Rs. 4320
C.I = P[(1 + R/100)^T - 1]
= 12000[(1 + 12/100)³ - 1]
= 12000[(28/25)³ - 1]
= 12000[(21952/15652) - 1]
= 12000 * 6327/15625
= Rs. 4853.136
Difference = 4859.136 - 4320
= Rs. 539.136