9th Grade > Mathematics
NUMBER SYSTEMS MCQs
Total Questions : 197
| Page 2 of 20 pages
Answer: Option D. -> 4.8
:
D
A rational numbercan be written in the form of pq where p and q are integers and q is not equal to zero. Rational numbers have their decimal expansions as either terminating or non-terminating but recurring.
π = 3.14159265358..., i.e., the digits after decimal point do not terminate and not recurring. Hence it is not rational
√2 is approximated to 1.414213562373095..., i.e., it cannot be expressed as a recurring and non-terminating decimal and henceis not rational.
20 is not defined and for a rational number, the denominator should be non-zero.
4.8 on the other hand, satisfiesall the properties of rational numbers.
:
D
A rational numbercan be written in the form of pq where p and q are integers and q is not equal to zero. Rational numbers have their decimal expansions as either terminating or non-terminating but recurring.
π = 3.14159265358..., i.e., the digits after decimal point do not terminate and not recurring. Hence it is not rational
√2 is approximated to 1.414213562373095..., i.e., it cannot be expressed as a recurring and non-terminating decimal and henceis not rational.
20 is not defined and for a rational number, the denominator should be non-zero.
4.8 on the other hand, satisfiesall the properties of rational numbers.
:
An irrational numberis a real number that cannot be expressed as a ratio of integers, i.e. as a fraction, where the denominator is different from zero. Therefore, irrational numbers, when written as decimal numbers, do not terminate, nor do they repeat. √2,√3 are examples of irrational numbers.
Answer: Option A. -> integer
:
A
Whole numbers comprise the set {0,1,2,3...} whereas integers comprise the set {... -2,-1,0,1,2,...}.
Thus, we can see that whole numbers are a sub-set of integers.
Hence, every whole number is an integer.
:
A
Whole numbers comprise the set {0,1,2,3...} whereas integers comprise the set {... -2,-1,0,1,2,...}.
Thus, we can see that whole numbers are a sub-set of integers.
Hence, every whole number is an integer.
Answer: Option C. -> All real numbers are irrational
:
C
Every irrational number is a real number but real numbers compriseof rational as well as irrational numbers. Moreover, any point on a number line represents a definite real number.
:
C
Every irrational number is a real number but real numbers compriseof rational as well as irrational numbers. Moreover, any point on a number line represents a definite real number.
Answer: Option C. -> 116
:
C
We know that (am)n=amn .
(256)−12=(28)−12(Since256=2×2×2×2×2×2×2×2=28)
=2(8×(−12))
=2−4
=116
:
C
We know that (am)n=amn .
(256)−12=(28)−12(Since256=2×2×2×2×2×2×2×2=28)
=2(8×(−12))
=2−4
=116
Answer: Option B. -> 5+2√6
:
B
We rationalise the denominator by dividing and multiplying the number by √2+√3.
So, we have
√2+√3√3−√2×√3+√2√3+√2
=(√3+√2)2√32−√22
=(√3)2+(√2)2+2√63−2
[Using the identity(a+b)2=a2+b2+2ab]
=5+2√6.
:
B
We rationalise the denominator by dividing and multiplying the number by √2+√3.
So, we have
√2+√3√3−√2×√3+√2√3+√2
=(√3+√2)2√32−√22
=(√3)2+(√2)2+2√63−2
[Using the identity(a+b)2=a2+b2+2ab]
=5+2√6.
Answer: Option D. -> 1 is a whole number
:
D
Natural numbers start from 1 and continue thereafter by adding 1 each time.
So1, 2,3,4,5... are all natural numbers.
All the natural numbers and "0" together are referred to as whole numbers. Hence 1 is a whole number.
Natural numbers, their negatives and 0 constitute the set of Integers.
:
D
Natural numbers start from 1 and continue thereafter by adding 1 each time.
So1, 2,3,4,5... are all natural numbers.
All the natural numbers and "0" together are referred to as whole numbers. Hence 1 is a whole number.
Natural numbers, their negatives and 0 constitute the set of Integers.
Answer: Option C. -> 725
:
C
The decimal expansion of 14 is 0.25 and the decimal expansion of13 is 0.333...
Now comparing with the decimal expansion 0.25 and 0.333... with the options:
a) Clearly, 0 is out of therange.
b) The decimal expansionof 18 is 0.125which is also out of therange.
c) The decimal expansionof 725 is 0.28, so itlies between14and 13 .
d) The decimal expansionof 15 is 0.2, so it isout of therange.
:
C
The decimal expansion of 14 is 0.25 and the decimal expansion of13 is 0.333...
Now comparing with the decimal expansion 0.25 and 0.333... with the options:
a) Clearly, 0 is out of therange.
b) The decimal expansionof 18 is 0.125which is also out of therange.
c) The decimal expansionof 725 is 0.28, so itlies between14and 13 .
d) The decimal expansionof 15 is 0.2, so it isout of therange.
Answer: Option A. -> 343729
:
A
(79)3=7×7×79×9×7⇒(79)3=343729
:
A
(79)3=7×7×79×9×7⇒(79)3=343729
Answer: Option D. -> 920
:
D
To convert 0.45 into a fraction:
0.45=45100
[Multiplying 0.45 with 100100]
Dividing thenumerator and the denominator by 5, we get
45100=920
∴0.45=920
:
D
To convert 0.45 into a fraction:
0.45=45100
[Multiplying 0.45 with 100100]
Dividing thenumerator and the denominator by 5, we get
45100=920
∴0.45=920