5th Grade > Mathematics
MONEY MCQs
:
D
Total amount = ₹ 550
Amount spent = ₹ 199
Money left with her = Total amount - amount spent
= ₹ 550 - ₹ 199
4/514/510/0− 1 9 9–––––––– 3 5 1––––––––
Therefore, money left with her is ₹ 351.
:
D
Cost of 100 g of flour=₹ 30
⇒Cost of 1 g of flour=₹ 30100=₹ 310
∴Cost of 350 g of flour=350×₹310
=35×₹3
=₹ 105
:
A
We need to split up ₹ 27 in terms of ₹ 5 and ₹ 2 coins.
6 coins of ₹ 2 = 6 x ₹ 2 = ₹ 12
To find out how many coins of ₹ 5 we need, we first subtract ₹ 12 from ₹ 27 .
₹ 27 - ₹ 12 = 15
We need this ₹ 15 in terms of ₹ 5 coins. To find the number of ₹ 5 coins, we divide 15 by 5.
∴ We need ₹ 15₹ 5=3 coins of ₹ 5.
i.e., ₹ 27 = 3 coins of ₹ 5 + 6 coins of ₹ 2
:
B
DenominationQuantityValue₹103₹10×3=₹30₹514₹5×14=₹70₹28₹2×8=₹16₹14₹1×4=₹4
For ₹ 120, she needs 6 notes of ₹ 20 as
6×₹ 20=₹ 120.
Therefore, she will get 6 twenty rupee notes.
:
B
15 two hundred rupee notes
=15×₹200=₹3000
9 five hundred rupee notes
=9×₹500=₹4500
When ₹ 3000 is deducted from ₹ 4500, we get:
4500−3000 –––––––– 1500 ––––––––
∴ 15 two hundred rupee notes is less than 9 five hundred rupee notes by ₹ 1500.
:
D
Money borrowed = ₹ 375
Glen gave it back to his brother in ₹ 5 coins.
Number of ₹ 5 coins=₹375₹5=75
Therefore, Glen gave 75 five rupee coins to make ₹ 375.
:
B
There are 10 five rupee coins in the box.
A took three coins.
So, A got 3 × ₹ 5 = ₹ 15.
B took five coins.
So, B got 5 × ₹ 5 = ₹ 25.
C took two coins.
So, C got 2 × ₹ 5 = ₹ 10.
:
D
Cost of 1 bottle of ketchup = ₹ 45
Cost of 3 bottle of ketchup = ₹ 45 × 3
= ₹ 135
Cost of 1 block of cheese = ₹ 215
Cost of 4 blocks of cheese = ₹ 215 × 4
= ₹ 860
Total cost = ₹ 135
+ ₹ 860
--------------
₹ 995
---------------
He gave ₹ 1000 to the shopkeeper.
He will get back ₹1000 - ₹995 = ₹ 5.
:
D
Total money with the team = ₹ 420
Cost of each gift = ₹ 70
Number of gifts they can buy=Total moneyCost of each gift
=₹ 420₹ 70=6
:
B
1 rupee is equal to 100 paise.