5th Grade > Mathematics
MONEY MCQs
Total Questions : 20
| Page 1 of 2 pages
Answer: Option D. -> 75
:
D
Money borrowed = ₹ 375
Glengave it back tohis brother in ₹ 5 coins.
Number of ₹5 coins=₹375₹5=75
Therefore, Glen gave 75 five rupee coins tomake ₹ 375.
:
D
Money borrowed = ₹ 375
Glengave it back tohis brother in ₹ 5 coins.
Number of ₹5 coins=₹375₹5=75
Therefore, Glen gave 75 five rupee coins tomake ₹ 375.
Answer: Option A. -> 3
:
A
We need to split up₹ 27 in terms of₹ 5 and₹ 2 coins.
6 coins of₹ 2 = 6 x₹ 2 =₹ 12
To find out how many coins of₹ 5 we need, we first subtract₹ 12 from₹ 27 .
₹ 27-₹ 12= 15
We need this₹ 15in terms of₹ 5 coins. To find the number of₹ 5 coins, we divide 15 by 5.
∴ We need ₹15₹5=3 coins of₹ 5.
i.e.,₹ 27 = 3coins of ₹5+ 6 coins of ₹2
:
A
We need to split up₹ 27 in terms of₹ 5 and₹ 2 coins.
6 coins of₹ 2 = 6 x₹ 2 =₹ 12
To find out how many coins of₹ 5 we need, we first subtract₹ 12 from₹ 27 .
₹ 27-₹ 12= 15
We need this₹ 15in terms of₹ 5 coins. To find the number of₹ 5 coins, we divide 15 by 5.
∴ We need ₹15₹5=3 coins of₹ 5.
i.e.,₹ 27 = 3coins of ₹5+ 6 coins of ₹2
Answer: Option B. -> 100
:
B
1 rupee is equal to 100 paise.
:
B
1 rupee is equal to 100 paise.
Answer: Option B. -> 6
:
B
DenominationQuantityValue₹103₹10×3=₹30₹514₹5×14=₹70₹28₹2×8=₹16₹14₹1×4=₹4
For ₹120, sheneeds 6 notes of ₹20as
6×₹20=₹120.
Therefore, she will get 6 twenty rupee notes.
:
B
DenominationQuantityValue₹103₹10×3=₹30₹514₹5×14=₹70₹28₹2×8=₹16₹14₹1×4=₹4
For ₹120, sheneeds 6 notes of ₹20as
6×₹20=₹120.
Therefore, she will get 6 twenty rupee notes.
Answer: Option D. -> 6
:
D
Total money with the team = ₹ 420
Cost of each gift = ₹ 70
Number of gifts they can buy=Total moneyCost of each gift
=₹420₹70=6
:
D
Total money with the team = ₹ 420
Cost of each gift = ₹ 70
Number of gifts they can buy=Total moneyCost of each gift
=₹420₹70=6
Answer: Option B. -> ₹ 1500
:
B
15 two hundred rupee notes
=15×₹200=₹3000
9 five hundred rupeenotes
=9×₹500=₹4500
When ₹ 3000 is deducted from ₹ 4500, we get:
4500−3000––––––––1500––––––––
∴ 15 two hundred rupee notes is less than 9 five hundred rupee notesby ₹1500.
:
B
15 two hundred rupee notes
=15×₹200=₹3000
9 five hundred rupeenotes
=9×₹500=₹4500
When ₹ 3000 is deducted from ₹ 4500, we get:
4500−3000––––––––1500––––––––
∴ 15 two hundred rupee notes is less than 9 five hundred rupee notesby ₹1500.
Answer: Option D. -> ₹ 105
:
D
Cost of 100 g of flour=₹30
⇒Cost of 1 g of flour=₹30100=₹310
∴Cost of 350 g of flour=350×₹310
=35×₹3
=₹105
:
D
Cost of 100 g of flour=₹30
⇒Cost of 1 g of flour=₹30100=₹310
∴Cost of 350 g of flour=350×₹310
=35×₹3
=₹105
Answer: Option B. -> A - ₹ 15 B - ₹ 25 C - ₹ 10
:
B
There are 10 five rupee coinsin the box.
A took three coins.
So, Agot3 × ₹ 5 = ₹ 15.
B took fivecoins.
So, B got5× ₹ 5 = ₹ 25.
C took twocoins.
So, C got2× ₹ 5 = ₹ 10.
:
B
There are 10 five rupee coinsin the box.
A took three coins.
So, Agot3 × ₹ 5 = ₹ 15.
B took fivecoins.
So, B got5× ₹ 5 = ₹ 25.
C took twocoins.
So, C got2× ₹ 5 = ₹ 10.
Answer: Option D. -> ₹ 351
:
D
Total amount = ₹ 550
Amount spent = ₹ 199
Money left with her = Total amount - amount spent
= ₹550 - ₹199
4/514/510/0−199––––––––351––––––––
Therefore, money left with her is₹351.
:
D
Total amount = ₹ 550
Amount spent = ₹ 199
Money left with her = Total amount - amount spent
= ₹550 - ₹199
4/514/510/0−199––––––––351––––––––
Therefore, money left with her is₹351.
Answer: Option D. -> Total cost - ₹ 995
He gets back ₹ 5.
:
D
Cost of 1 bottle of ketchup = ₹45
Cost of 3 bottle of ketchup = ₹ 45 × 3
= ₹135
Cost of 1 block of cheese= ₹215
Cost of 4 blocks of cheese = ₹ 215 × 4
= ₹860
Total cost = ₹135
+ ₹860
--------------
₹995
---------------
He gave₹ 1000 to the shopkeeper.
He will get back ₹1000 - ₹995 =₹ 5.
:
D
Cost of 1 bottle of ketchup = ₹45
Cost of 3 bottle of ketchup = ₹ 45 × 3
= ₹135
Cost of 1 block of cheese= ₹215
Cost of 4 blocks of cheese = ₹ 215 × 4
= ₹860
Total cost = ₹135
+ ₹860
--------------
₹995
---------------
He gave₹ 1000 to the shopkeeper.
He will get back ₹1000 - ₹995 =₹ 5.