Quantitative Aptitude
MENSURATION MCQs
Regular Polygons, Triangles, Circles
Let the length and the breadth of the rectangle be 4x cm and 3x respectively.(4x)(3x) = 691212x2 = 6912 x2 = 576 = 4 * 144 = 22 * 122 (x > 0)
=> x = 2 * 12 = 24Ratio of the breadth and the areas = 3x : 12x2 = 1 : 4x = 1: 96.
Let the breadth of the plot be b m.Length of the plot = 3 b m(3b)(b) = 8673b2 = 867 b2 = 289 = 172 (b > 0)b = 17 m.
Let the length and the breadth of the floor be l m and b m respectively.l = b + 200% of b = l + 2b = 3bArea of the floor = 324/3 = 108 sq ml b = 108 i.e., l * l/3 = 108l2 = 324 => l = 18.
Length of the first carpet = (1.44)(6) = 8.64 cmArea of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)= 51.84(1.4)(5/4) sq m = (12.96)(7) sq mCost of the second carpet = (45)(12.96 * 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
Let the radii of the smaller and the larger circles be s m and l m respectively. 2âˆs = 264 and 2âˆl = 352 s = 264/2∠and l = 352/2∠Difference between the areas = âˆl2 - âˆs2 = âˆ{1762/âˆ2 - 1322/âˆ2} = 1762/∠- 1322/∠= (176 - 132)(176 + 132)/∠= (44)(308)/(22/7) = (2)(308)(7) = 4312 sq m
Let the side of the square be a cm. Parameter of the rectangle = 2(16 + 14) = 60 cm
Parameter of the square = 60 cm i.e. 4a = 60 A = 15 Diameter of the semicircle = 15 cm Circimference of the semicircle = 1/2(âˆ)(15) = 1/2(22/7)(15) = 330/14 = 23.57 cm to two decimal places
Area of the path = Area of the outer circle - Area of the inner circle = âˆ{4/2 + 25/100}2 - âˆ[4/2]2 = âˆ[2.252 - 22]
= âˆ(0.25)(4.25) { (a2 - b2 = (a - b)(a + b) } = (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq m
Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm. a2 = 784 = (4)(196) = (22).(142) a = (2)(14) = 28 a = 2l, l = a/2 = 14 l = (7/3)s Therefore s = (3/7)(l) = 6
Circumference of the smaller circle = 2âˆs = 12∠cm.
Along one edge, the number of small cubes that can be cut = 100/10 = 10 Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000
Area of the square = s * s = 5(125 * 64)=> s = 25 * 8 = 200 cmPerimeter of the square = 4 * 200 = 800 cm.