Mensuration(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

MENSURATION MCQs

Regular Polygons, Triangles, Circles

Total Questions : 254 | Page 23 of 26 pages

Question 221. In an equilateral triangle ABC, G is the centroid. Each side of the triangle is 6 cm. The length of AG is:

$$2\sqrt 2 $$ cm
$$3\sqrt 2 $$ cm
$$2\sqrt 3 $$ cm
$$3\sqrt 3 $$ cm

Discuss Question

Answer: Option C. -> $$2\sqrt 3 $$ cm

Question 222. If the measure of the angles of a triangle are in the ratio 1 : 2 : 3 and if the length of the smallest side of the triangle is 10 cm, then the length of the longest side is:

20 cm
25 cm
30 cm
35 cm

Discuss Question

Answer: Option A. -> 20 cm

Question 223. In a triangle ABC, ∠A = 70°, ∠B = 80° and D is the incenter of ΔABC, ∠ACB = 2x° and ∠BDC = y°. The values of x and y, respectively are:

15°, 130°
15°, 125°
35°, 40°
30°, 150°

Discuss Question

Answer: Option B. -> 15°, 125°

Question 224. In case of an acute angled triangle, its orthocenter lies:

Inside the triangle
Outside the triangle
On the triangle
On one of the vertex of the triangle

Discuss Question

Answer: Option A. -> Inside the triangle

Question 225. What is the are of an equilateral triangle of side 16 cm?

48√3 cm2
128√3 cm2
9.6√3 cm2
64√3 cm2
None of these

Discuss Question

Answer: Option D. -> 64√3 cm2

Area of an equilateral triangle = √3/4 S² If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm²;

Question 226. The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?

25 cm2
42 cm2
49 cm2
70 cm2
None of these

Discuss Question

Answer: Option E. -> None of these

Area of a triangle = r * sWhere r is the inradius and s is the semi perimeter of the triangle.Area of triangle = 2.5 * 28/2 = 35 cm²

Question 227. If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?

120 cm2
130 cm2
312 cm2
315 cm2
None of thesae

Discuss Question

Answer: Option A. -> 120 cm2

The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.Area of the triangle = 1/2 * 24 * 10 = 120 cm²

Question 228. Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.

225 cm2
275 cm2
285 cm2
315 cm2
None of these

Discuss Question

Answer: Option C. -> 285 cm2

Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (15)
= 285 cm²

Question 229. Find the area of a parallelogram with base 24 cm and height 16 cm.

262 cm2
384 cm2
192 cm2
131 cm2
None of these

Discuss Question

Answer: Option B. -> 384 cm2

Area of a parallelogram = base * height = 24 * 16 = 384 cm²

Question 230. The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?

8
12
6
2
None of these

Discuss Question

Answer: Option D. -> 2

Let the sides of the rectangle be l and b respectively.From the given data, (√l² + b²) = (1 + 108 1/3 %)lb => l² + b² = (1 + 325/3 * 1/100)lb= (1 + 13/12)lb= 25/12 lb=> (l² + b²)/lb = 25/12 12(l² + b²) = 25lb Adding 24lb on both sides 12l² + 12b² + 24lb = 49lb 12(l² + b² + 2lb) = 49lb but 2(l + b) = 28 => l + b = 14 12(l + b)² = 49lb => 12(14)² = 49lb => lb = 48 Since l + b = 14, l = 8 and b = 6 l - b = 8 - 6 = 2m.