12th Grade > Chemistry
IONIC EQUILIBRIUM MCQs
Total Questions : 30
| Page 3 of 3 pages
Answer: Option C. -> BF3
:
C
BF3 has vacant orbital and incomplete octethence act as Lewis acid
:
C
BF3 has vacant orbital and incomplete octethence act as Lewis acid
Answer: Option A. -> formation of water
:
A
Net reaction of acid - base neutralization according to Arrhenius theory is formation of water
H++OH−→H2O
:
A
Net reaction of acid - base neutralization according to Arrhenius theory is formation of water
H++OH−→H2O
Answer: Option D. -> 1.0 × 10−7molL−1
:
D
BOH⇋B++OH−
Initially,
BOH=C, B+ = 0 and OH− = 0
At Equilibrium
BOH=C−Cα, B+ = Cα and OH− = Cα
Kb=C2α2C(1−α) = Cα2assuming α<<1; 1−α∼ 1
10−12 = 10−2×α2; α2 = 10−10; α= 10−5
OH− = Cα = 0.01×10−5=10−7
:
D
BOH⇋B++OH−
Initially,
BOH=C, B+ = 0 and OH− = 0
At Equilibrium
BOH=C−Cα, B+ = Cα and OH− = Cα
Kb=C2α2C(1−α) = Cα2assuming α<<1; 1−α∼ 1
10−12 = 10−2×α2; α2 = 10−10; α= 10−5
OH− = Cα = 0.01×10−5=10−7
Answer: Option C. -> CH3−
:
C
CH4 weakest acid among H2O, OH−, CH4& NH3hence CH3−is strongest base
:
C
CH4 weakest acid among H2O, OH−, CH4& NH3hence CH3−is strongest base
Answer: Option A. -> [Ag+]2[CrO2−4]
:
A
Ag2CrO4⇋2[Ag+]+[CrO2−4]
Hence K[sp]=[Ag+]2+[CrO2−4]
:
A
Ag2CrO4⇋2[Ag+]+[CrO2−4]
Hence K[sp]=[Ag+]2+[CrO2−4]
Answer: Option A. -> 1 × 10−8
:
A
K=α2C1−α;α=0.01100
∴K=α2C=[0.01100]2×1=1×10−8
:
A
K=α2C1−α;α=0.01100
∴K=α2C=[0.01100]2×1=1×10−8
Answer: Option B. -> 4a3
:
B
CaF2⇋Ca2++2F−;
KspforCaF2 = [Ca2+][F−]2 = a×(2a)2=4a3
:
B
CaF2⇋Ca2++2F−;
KspforCaF2 = [Ca2+][F−]2 = a×(2a)2=4a3
Answer: Option D. -> Both sulphides precipitate
:
D
The concentration of S2−ions in group II is lowered by maintaining acidic
medium in the presence of NH4Cl. The ionization of H2Sis supressed due
tocommon ion effect. So the ionic product is less than solubility product.
:
D
The concentration of S2−ions in group II is lowered by maintaining acidic
medium in the presence of NH4Cl. The ionization of H2Sis supressed due
tocommon ion effect. So the ionic product is less than solubility product.
Answer: Option D. -> Arrhenius
:
D
Arrhenius proposed the theory of ionisation.
:
D
Arrhenius proposed the theory of ionisation.
Answer: Option D. -> 3.2 × 10−11
:
D
Ksp for CaF2=4s3=4×[2×10−4]3=3.2×10−11
:
D
Ksp for CaF2=4s3=4×[2×10−4]3=3.2×10−11
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