Question
The solubility of CaF2 is a moles/litre. Then its solubility product is .....
Answer: Option B
:
B
CaF2⇋Ca2++2F−;
KspforCaF2 = [Ca2+][F−]2 = a×(2a)2=4a3
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:
B
CaF2⇋Ca2++2F−;
KspforCaF2 = [Ca2+][F−]2 = a×(2a)2=4a3
Was this answer helpful ?
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