Quantitative Aptitude
HCF AND LCM MCQs
Problems On Hcf And Lcm, H.C.F And L.C.M. Of Numbers, Lcm & Hcf, Hcf And Lcm
Total Questions : 1401
| Page 12 of 141 pages
Answer: Option B. -> 15110
- Here (48 - 38) = 10, (60 - 50) = 10, (72 - 62) = 10, (108 - 98) = 10 & (140 - 130) = 10.
Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10
= 15120 – 10 = 15110
- Here (48 - 38) = 10, (60 - 50) = 10, (72 - 62) = 10, (108 - 98) = 10 & (140 - 130) = 10.
Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10
= 15120 – 10 = 15110
Answer: Option C. -> 308
- Other number = 11 x 7700 = 308 275
- Other number = 11 x 7700 = 308 275
Answer: Option C. -> 23
- L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23
- L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23
Answer: Option D. -> 0.35
- Given numbers with two decimal places are : 1.75, 5.60 and 7.00. Without decimal places, these numbers are : 175, 560 and 700, whose H.C.F. is 35. H.C.F of given numbers = 0.35
The Highest Common Factor (HCF) of any two or more given numbers is the largest number that divides each one of them completely. In other words, it is the largest number that is a common factor of all the given numbers.
In this case, the HCF of 1.75, 5.6 and 7 is 0.35.
To find the HCF of these numbers, we will use the prime factorization method. Prime factorization is the process of finding the prime numbers that multiply together to produce the given number.
Let us start by finding the prime factorization of each of the three numbers:
1.75:
1.75 = 2 × 2 × 2 × 0.875
5.6:
5.6 = 2 × 2 × 2 × 2 × 1.4
7:
7 = 7
Now, let us find the HCF of these numbers:
HCF = 2 × 2 × 2 × 0.875
HCF = 0.35
Thus, the HCF of 1.75, 5.6 and 7 is 0.35.
Explanation:
• The HCF of any two or more given numbers is the largest number that divides each one of them completely.
• The prime factorization method is used to find the HCF of the given numbers.
• In this case, the HCF of 1.75, 5.6 and 7 is 0.35.
If you think the solution is wrong then please provide your own solution below in the comments section .
Answer: Option D. -> 46 minutes 12 seconds
- L.C.M. of 252, 308 and 198 = 2772. So, A, B and C will again meet at the starting point in 2772 see i.e., 46 min. 12 sec
- L.C.M. of 252, 308 and 198 = 2772. So, A, B and C will again meet at the starting point in 2772 see i.e., 46 min. 12 sec
Answer: Option B. -> 9831
- Greatest number of 4 digits is 9999, L.C.M. of 4, 7 and 13 = 364 On dividing 9999 by 364, remainder obtained is 171. Greatest number of 4 digits divisible by 4, 7 and 13 = (9999 – 171) = 9828 Hence, required number = (9828 + 3) = 9831
- Greatest number of 4 digits is 9999, L.C.M. of 4, 7 and 13 = 364 On dividing 9999 by 364, remainder obtained is 171. Greatest number of 4 digits divisible by 4, 7 and 13 = (9999 – 171) = 9828 Hence, required number = (9828 + 3) = 9831
Answer: Option A. -> 4
Answer: Option C. -> 322
Answer: Option C. -> 9600
Answer: Option A. -> 4
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