Question
The largest four digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case, is?
Answer: Option B
- Greatest number of 4 digits is 9999, L.C.M. of 4, 7 and 13 = 364 On dividing 9999 by 364, remainder obtained is 171. Greatest number of 4 digits divisible by 4, 7 and 13 = (9999 – 171) = 9828 Hence, required number = (9828 + 3) = 9831
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- Greatest number of 4 digits is 9999, L.C.M. of 4, 7 and 13 = 364 On dividing 9999 by 364, remainder obtained is 171. Greatest number of 4 digits divisible by 4, 7 and 13 = (9999 – 171) = 9828 Hence, required number = (9828 + 3) = 9831
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