Question
3×46+4×512−5×710 =
Answer: Option C
:
C
3×46+4×512−5×7103×46+4×512−5×710∴42+53−72∴LCM of 2×3=6∴4×32×3+5×23×2−7×32×312+10−2122−216=16
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:
C
3×46+4×512−5×7103×46+4×512−5×710∴42+53−72∴LCM of 2×3=6∴4×32×3+5×23×2−7×32×312+10−2122−216=16
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