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12th Grade > Physics

ELECTRIC CHARGES FIELDS AND GAUSS LAW MCQs

Total Questions : 30 | Page 3 of 3 pages
Question 21. Electric lines of force about negative point charge are
 
  1.    Circular, anticlockwise
  2.    Circular, clockwise
  3.    Radial, inward 
  4.    Radial, outward
 Discuss Question
Answer: Option C. -> Radial, inward 
:
C
Electric Lines Of Force About Negative Point Charge Are 
Question 22.   
 
 
 Discuss Question
Answer: Option C. -> Radial, inward 
:
D
The force is perpendicular to the displacement.
Question 23. Three positive charges of equal value q are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in                                              
 Discuss Question
Answer: Option C. -> Radial, inward 
:
C
Option (a) shows lines of force starting from one positive charge and terminating at another. Option (b) has one line of force making closed loop. Option (d) shows all lines making closed loops. All these are not correct. Only option (c) is correct.
Question 24. Two parallel plane sheets 1 and 2 carry uniform charge densities σ1 and σ2 as in fig electric field in the region marked II is (σ1 > σ2)
Two Parallel Plane Sheets 1 And 2 Carry Uniform Charge Densi...
  1.    −(σ1+σ2)2ϵ0
  2.    −(σ1 σ2)2ϵ0
  3.    (σ1+σ2)2ϵ0
  4.    (σ1−σ2)2ϵ0
  5.    If assertion is false but reason is true.
 Discuss Question
Answer: Option D. -> (σ1−σ2)2ϵ0
:
D
E=E1E2
=σ12ϵ0σ22ϵ0
E=σ1σ22ϵ0
Question 25. A cube is arranged such that its length, breadth and height are along X, Y and Z directions. One of its corners is situated at the origin. Length of each side of the cube is 25 cm. The components of electric field are Ex=400 2N/C,Ey=0 and Ez=0 respectively. Find the flux coming out of the cube at one end.
  1.    25
  2.    25√2
  3.    25√2
  4.    zero
  5.    If assertion is false but reason is true.
 Discuss Question
Answer: Option C. -> 25√2
:
C
Φx=ExAcos(0)
=4002×14×14
=400216=252
Question 26. The minimum charge on an object is 
  1.    1 coulomb
  2.    1 stat coulomb
 Discuss Question
Answer: Option C. -> 25√2
:
C
This is the charge of an electron. It is the minimum charge possible. All other charges are its integral multiple.
Question 27. The electric field inside a spherical shell of uniform surface charge density is 
 
  1.    Zero 
  2.    Constant, less than zero
  3.    Directly proportional to the distance from the centre
  4.    None of the above
 Discuss Question
Answer: Option A. -> Zero 
:
A
All charge resides on the outer surface so that according to Gauss law, electric field inside a shell is zero.
Question 28. The intensity of the electric field required to keep a water drop of radius 105 cm, just suspended in air when charged with one electron is approximately (g = 10newton / kg, e=1.6×1019 coulomb)
  1.    260 volt / cm
  2.    260 newton / coulomb
  3.    130 volt / cm
  4.    130 newton / coulomb
  5.    If assertion is false but reason is true.
 Discuss Question
Answer: Option B. -> 260 newton / coulomb
:
B
For balance mg=eEE=mge
Also m=43πr3d=43×227×(107)3×1000kg
E=4/3×22/7×(107)3×1000×101.6×1019=260N/C
Question 29. Assertion : Electric lines of force cross each other.
Reason :   Electric field at a point superimpose to give one resultant electric field.     
  1.    If both assertion and reason are true and the reason is the correct explanation of the assertion.
  2.    If both assertion and reason are true but reason is not the correct explanation of the assertion.
  3.    If assertion is true but reason is false.
  4.    If the assertion and reason both are false.
  5.    If assertion is false but reason is true.
 Discuss Question
Answer: Option E. -> If assertion is false but reason is true.
:
E
If electric lines of forces cross each other, then the electric field at the point of intersection will have two direction simultaneously which is not possible physically.
Question 30. A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux from the curved surface of the cylinder is given by
  1.    2πR2E
  2.    πR2E
  3.    (πR2−πR)E
  4.    zero
  5.    If assertion is false but reason is true.
 Discuss Question
Answer: Option D. -> zero
:
D
Φ=Φ1+Φ2+Φ3Φ1=EAcos180=EA
=EA+EA+0Φ2=EAcos0=+EA
=0Φ3=EAcos90=0(Since Angle between E and A(Lateral surface) is always 90)
We only need to find Φ3
A Cylinder Of Radius R And Length L Is Placed In A Uniform E...

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