12th Grade > Physics
ELECTRIC CHARGES FIELDS AND GAUSS LAW MCQs
Total Questions : 30
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Answer: Option A. -> A force and a torque
:
A
As the dipole will feel two forces which are although opposite but not equal.
Therefore, A net force will be there and as these forces act at different points of a body. A torque is also there.
:
A
As the dipole will feel two forces which are although opposite but not equal.
Therefore, A net force will be there and as these forces act at different points of a body. A torque is also there.
Answer: Option B. -> Gives electrons to silk
:
B
On rubbing glass rod with silk, excess electron transferred from glass to silk. So glass rod becomes positive and silk becomes negative.
:
B
On rubbing glass rod with silk, excess electron transferred from glass to silk. So glass rod becomes positive and silk becomes negative.
Answer: Option D. -> 0.5 micro-coulomb
:
D
E=9×109×Qr2⇒500=9×109×Q(3)2⇒Q=0.5μC
:
D
E=9×109×Qr2⇒500=9×109×Q(3)2⇒Q=0.5μC
Answer: Option D. -> If the assertion and reason both are false.
:
D
Gravitational force is the dominating force in nature and not coulomb's force. Gravitational force is the weakest force. Also, Coulomb's force>> gravitational force.
:
D
Gravitational force is the dominating force in nature and not coulomb's force. Gravitational force is the weakest force. Also, Coulomb's force>> gravitational force.
Answer: Option C. -> The magnitude of velocity of the electron will first decrease and then increase
:
C
Aselectric field applies the force on electron in the direction opposite to it’s motion, the velocity of the electron will decrease.
:
C
Aselectric field applies the force on electron in the direction opposite to it’s motion, the velocity of the electron will decrease.
Answer: Option D. -> They have physical existence
:
D
Thereis no proof that they exist, these are just imaginary lines.
:
D
Thereis no proof that they exist, these are just imaginary lines.
Answer: Option C. -> 3Q4πϵ0R2
:
C
We only need to consider the E contribution due to sphere.
Shell gives zero contribution to E at any point inside it.
Use direct formula.
E=14πϵ03QR2
E=3Q4πϵ0R2
:
C
We only need to consider the E contribution due to sphere.
Shell gives zero contribution to E at any point inside it.
Use direct formula.
E=14πϵ03QR2
E=3Q4πϵ0R2
Answer: Option C. -> Equal to that in copper
:
C
Since both are metals so equal amount of charge will induce on them.
:
C
Since both are metals so equal amount of charge will induce on them.