Reasoning Aptitude
DIRECTION SENSE TEST MCQs
Direction & Distance Sense Test
Total Questions : 1290
| Page 127 of 129 pages
Question 1261. Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?
Answer: Option A. -> 65 km
Required Distance
= DF
= 150 - (25 + 25 + 35)
= 150 - 85
= 65 km
Required Distance
= DF
= 150 - (25 + 25 + 35)
= 150 - 85
= 65 km
Answer: Option B. -> 5 feet
Required Distance
= AD
= √{32 + (14 - 10)2}
= √(9 + 16)
= 5 ft
Required Distance
= AD
= √{32 + (14 - 10)2}
= √(9 + 16)
= 5 ft
Answer: Option B. -> South
The journey was started from the South.
The journey was started from the South.
Answer: Option B. -> South
Hence X will face in the end towards South.
Hence X will face in the end towards South.
Answer: Option B. -> 15 km
Required Distance
= AE
= 5 + 10
= 15 km
Required Distance
= AE
= 5 + 10
= 15 km
Answer: Option A. -> North
Therefore university is in North.
Therefore university is in North.
Answer: Option A. -> South-East
Therefore, D's house is in the South-East direction of A.
Therefore, D's house is in the South-East direction of A.
Answer: Option A. -> North
In the morning sun rises in the East. Hence then any shadow falls in the West. Since Nikharia's shadow was exactly to the right of Nivedita. Hence Nikharia is facing towards North.
In the morning sun rises in the East. Hence then any shadow falls in the West. Since Nikharia's shadow was exactly to the right of Nivedita. Hence Nikharia is facing towards North.
Question 1269. A child went 90 m in the East to look for his father, then he turned right and went 20 m. After this he turned right and after going 30 m he reached to his uncle's house. His father was not there. From there he went 100 m to his north and met his father. How far did he meet his father from the starting point?
Answer: Option B. -> 100 m
Required Distance
= AE
= √(AG2 + EG2)
= √{(90 - 30)2 + (100 - 20)2}
= √{(60)2 + (80)2}
= √(3600 + 6400)
= √10000
= 100 m
Required Distance
= AE
= √(AG2 + EG2)
= √{(90 - 30)2 + (100 - 20)2}
= √{(60)2 + (80)2}
= √(3600 + 6400)
= √10000
= 100 m
Answer: Option B. -> South
Sun rises in the east in the morning. Since the shadow of Suresh falls to his right. So he is facing South.
Sun rises in the east in the morning. Since the shadow of Suresh falls to his right. So he is facing South.
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