Reasoning Aptitude
DIRECTION SENSE TEST MCQs
Direction & Distance Sense Test
Total Questions : 1290
| Page 124 of 129 pages
Answer: Option A. -> 10 metres West
Answer: (a)The movements of Sachin are as shown in figure (P to B, B to C,
C to D and D to Q).Clearly, distance of Q from P = PQPQ = (DQ –
PD) = (DQ – BC) = (40 – 30) m = 10 m.Also, Q is to the West of P.So, Q is 10 m West of P.
Answer: (a)The movements of Sachin are as shown in figure (P to B, B to C,
C to D and D to Q).Clearly, distance of Q from P = PQPQ = (DQ –
PD) = (DQ – BC) = (40 – 30) m = 10 m.Also, Q is to the West of P.So, Q is 10 m West of P.
Answer: Option A. -> $ 10√5 m, $north-west
Answer: (a)
Answer: (a)
Question 1233. Town D is 13 Km. towards the East of town A. A bus starts from town A travels 8 Km. towards West and takes a right turn. After taking the right turn, it travels 5 Km. and reaches town B. From town B the bus takes a right turn again, travels 21 Km. and stops. How far and towards which direction must the travel to reach town D?
Answer: Option A. -> 5 Km. towards South
Answer: (a)5 km towards south.
Answer: (a)5 km towards south.
Answer: Option B. -> 10m, north east
Answer: (b)
Answer: (b)
Answer: Option A. -> $5√ 2 km$
Answer: (a)$X^2 = 5^2 + 5^2$$X = √ 50 = 5√ 2$
Answer: (a)$X^2 = 5^2 + 5^2$$X = √ 50 = 5√ 2$
Answer: Option B. -> South
Answer: (b)
Answer: (b)
Answer: Option C. -> 1m north, Mother
Answer: (c)
Answer: (c)
Answer: Option E. -> None of these
Answer: (e)
Answer: (e)
Answer: Option A. -> south-west
Answer: (a)
Answer: (a)
Answer: Option D. -> 70 km
Answer: (d)Required distance
= 30 + 25 + 15 = 70 km
Answer: (d)Required distance
= 30 + 25 + 15 = 70 km
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