12th Grade > Physics
CURRENT ELECTRICITY MCQs
Electricity And Circuits
Total Questions : 60
| Page 2 of 6 pages
Answer: Option A. -> True
:
A
Electric current is a flow of charges. We know current flows from the positive terminal to the negative terminal of a cell. The direction of flow of current is opposite to the direction of flow of electrons. Hence, in a closed circuit, electrons flow from the negative terminal to the positive terminal of a cell.
:
A
Electric current is a flow of charges. We know current flows from the positive terminal to the negative terminal of a cell. The direction of flow of current is opposite to the direction of flow of electrons. Hence, in a closed circuit, electrons flow from the negative terminal to the positive terminal of a cell.
Answer: Option D. -> positive
:
D
Electric cell is a device which converts chemical energy into electrical energy. All electric cells have two terminals.Metal cap on an electric cell is considered as thepositive terminal of the cell whereas metal disc of an electric cell is considered as the negative terminal of the cell.
:
D
Electric cell is a device which converts chemical energy into electrical energy. All electric cells have two terminals.Metal cap on an electric cell is considered as thepositive terminal of the cell whereas metal disc of an electric cell is considered as the negative terminal of the cell.
Answer: Option A. -> True
:
A
Electric current can only flow when there is a closed path. The flow of electrons through the filament of a bulb generates heat and light. Hence, an electric bulb glows only when the circuit is closed.
:
A
Electric current can only flow when there is a closed path. The flow of electrons through the filament of a bulb generates heat and light. Hence, an electric bulb glows only when the circuit is closed.
Answer: Option A. -> True
:
A
The two terminals of the battery should not be connected to each other without connecting it through a bulb or switch because the chemicals in the cell gets used up very fast and the cell stops working in a short period of time.
:
A
The two terminals of the battery should not be connected to each other without connecting it through a bulb or switch because the chemicals in the cell gets used up very fast and the cell stops working in a short period of time.
Answer: Option A. -> copper
:
A
Switches are devices used to make or break the electric circuit. Sockets are devices which allows the electric equipmentto get connected to the power sources. Electric plugs are present in the electric equipments such that it can be connected to the sockets to complete the circuit. Internal parts ofswitches, electrical plugs, and sockets are made up of conductors, such as copper,to allowelectricity to pass through them.
:
A
Switches are devices used to make or break the electric circuit. Sockets are devices which allows the electric equipmentto get connected to the power sources. Electric plugs are present in the electric equipments such that it can be connected to the sockets to complete the circuit. Internal parts ofswitches, electrical plugs, and sockets are made up of conductors, such as copper,to allowelectricity to pass through them.
Answer: Option A. -> R3
:
A
Resistance R,(R+R)=2R,(R+R)=2R and R are in parallel
Hence effective resistance is given by
1Reff=1R+12R+12R+1R
which gives Reff=R3
:
A
Resistance R,(R+R)=2R,(R+R)=2R and R are in parallel
Hence effective resistance is given by
1Reff=1R+12R+12R+1R
which gives Reff=R3
Answer: Option D. -> 24 ohm
:
D
The given circuit is Wheatstone's bridge.The current through the galvanometer will be zero if the bridge is balanced
PQ+RS where P = 2+3 =5ohm, Q = 10ohm and R=4ohm
The value of S is given by
510=4S
or S= 8 ohm
thus the effective resistance of the parallel combination of 12 ohm and x ohm must be 8 ohm
therefore
112+1x=18
which gives x = 24ohm
:
D
The given circuit is Wheatstone's bridge.The current through the galvanometer will be zero if the bridge is balanced
PQ+RS where P = 2+3 =5ohm, Q = 10ohm and R=4ohm
The value of S is given by
510=4S
or S= 8 ohm
thus the effective resistance of the parallel combination of 12 ohm and x ohm must be 8 ohm
therefore
112+1x=18
which gives x = 24ohm
Answer: Option C. -> V3
:
C
In the steady state no current flows in the branch containing the capacitor .Thus the current say l flows in the branches containing R and 2R. Applying Kirchoff's second rule to the loop abcdefa
2V-I(2R)-IR-V=0
l=V3R
Potential drop across capacitor =2V-V-l(2R)=V−v3R×2R
=V−2v3=v3
:
C
In the steady state no current flows in the branch containing the capacitor .Thus the current say l flows in the branches containing R and 2R. Applying Kirchoff's second rule to the loop abcdefa
2V-I(2R)-IR-V=0
l=V3R
Potential drop across capacitor =2V-V-l(2R)=V−v3R×2R
=V−2v3=v3
Answer: Option A. -> a
:
A
The voltmeter must be connected in parallel with the resistor and the ammeter must be connected in series with the resistor
:
A
The voltmeter must be connected in parallel with the resistor and the ammeter must be connected in series with the resistor
Answer: Option C. -> 1.2
:
C
rR=l1−l2l2
here R=10 ohm
l1 = 560cm
l2 =560-60=500cm
r=R×(l1−l2l2)
=10×(560−500500)
=1.2ohm
:
C
rR=l1−l2l2
here R=10 ohm
l1 = 560cm
l2 =560-60=500cm
r=R×(l1−l2l2)
=10×(560−500500)
=1.2ohm
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