Answer: Option A. ->
:

Calculations: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Let the Fanta, Coca-Cola and Sprite bottles be 8x, 15x, 12x.
The total number of Fanta bottle is 120.
So, 8x = 120
x = 15
Then coca cola bottles $=15\times 15=225$
Sprite bottles $=12\times 15=180$.
So, the total number of bottle is 120 + 225 + 180 = 525.
Alternative Method:
Let '$x$' be the total number of bottles.
Now, the bottles are in the ratio 8: 15: 12
The sum of these numbers = 8 + 15 + 12 = 35
The number of Fanta bottles = 120
Also number of Fanta bottles=$\frac{8}{35}\times x$ = 120
So, $x=\frac{35}{8}\times 120=525$
Hence the total number of bottles is 525.

Answer: Option A. ->
:

Calculations: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Cost price = ₹ 12000, overhead charges = ₹ 2850
$\therefore$ Total cost price = ₹ (12000 + 2850) = 14850
Selling Price = ₹ 13860
Selling Price < Cost Price $\Rightarrow$ Loss
$\therefore$ Loss = Cost price - Selling price
$\Rightarrow$ Loss = ₹ (14850-13860) = ₹ 990
Loss percentage = $\frac{Loss}{CostPrice}\times 100$
 Loss percentage = $\frac{990}{14850}\times 100$ = 6.7 %
So, Ravi incurred a loss of 6.7%.

Answer: Option A. ->
:

Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark

Number of questions Aarush used to solve initially = 4 questions in 16 minutes
Time needed to solve a question = $\frac{16}{4}$ = 4 minutes

Number of questions Aarush can solve after practising = 6 questions in 18 minutes
Time needed to solve a question = $\frac{18}{6}$ = 3 minutes

Decrease in time to solve a single question = 4 - 3 = 1 minutes.
Therefore, the percentage decrease is given by
Decrease Percent = $\frac{\text{amount decreased}}{\text{Original or base}}\times 100$
On substituting the values, we get:
Decrease in percentage = $\frac{1}{4}\times 100$ = 25%
Hence, after practising Aarush reduced 25% of the time to solve a single question.

Answer: Option A. ->
:

Concept: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
Given that:
 Marked price  of the toy = ₹ 200
Discount  =   20%.

Discount = Discount % of Marked Price 

               = $\frac{20}{100}\times 200$

                = ₹ 40
Selling price = Marked Price - Discount 
                    = ₹( 200- 40 ) 

                    = ₹ 160
It is given that even after the discount the shopkeeper was making a profit of 60%.
So, the cost price of the toy
$=\frac{100}{160}\times 160=₹100$
Hence, the actual price of the toy is ₹ 100.

Answer: Option A. ->
:

Steps: 2 Mark
Price before discount: 1 Mark
Selling price: 1 Mark
Given that,
Radhika bought a new mobile phone and saved  ₹1000 when a discount of 10$\%$ was given.
We can infer from the above statement that 10$\%$ of the original price =  ₹ 1000
10$\%$ of the original price =  ₹ 1000
Let the price be P.
$\Rightarrow 10\%\text{of P = 1000}$
$\Rightarrow \frac{10}{100}\times \text{P = 1000}$
$\Rightarrow \text{P}=\frac{1000\times 100}{10}$
$\Rightarrow P$ =  ₹ 10000
Hence the original price of the mobile phone is  ₹ 10000.
Now, the original price of the mobile phone is  ₹ 10000.
Discount given =  ₹ 1000
$\therefore$ The Selling price or the price at which the phone was sold = Original Price - Discount
On substituting the values we get:
Selling Price = 10000 - 1000 =  ₹ 9000
Hence, the mobile phone was sold at  ₹ 9000.

Answer: Option A. ->
:

Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Here,
It is given that Soham bought a sofa for Rs6500.
He paid Rs 975 as interest in three years.
Let, Principal amount be 'P' = Rs 6500
Interest be 'I' = Rs 975
Time be 'T' = 3 years
The rate of interest =?
Let the rate of interest be 'R'.
We know that,
$I=\frac{P\times T\times R}{100}$
$\Rightarrow R=\frac{I\times 100}{P\times T}$
$\Rightarrow R=\frac{975\times 100}{6500\times 3}$
$\Rightarrow R=5$
Hence the rate of interest is 5%.

Answer: Option A. ->
:

Steps: 2 Marks
Answer: 1 Mark each
Given that:
Meet saves ₹ 4000 from her salary, which is 10% of her salary. 
Let Meet’s salary be ₹  $x$
Given that,
$10\%ofx=4000$
$\frac{10}{100}\times x=4000$
$\frac{x}{10}=4000$
$x=4000\times 10=₹40000$
Therefore, Meet’s salary is ₹ 40,000.
Her net expenditure = Salary - savings = 40000 - 4000 = ₹ 36,000
Now in order to buy a bike Meet starts saving $30\%$ of her salary.
Her salary is ₹ 40,000.
The total amount she starts saving monthly = $\frac{30}{100}\times 40,000$ = $₹12,000$
Her net saving monthly is ₹ 12,000.

Answer: Option A. ->
:
Formula: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
Given,
Meena pays an interest of  ₹ 45 for one year.
The rate of interest is 9 %
Interest =  ₹ 45
Time = 1 year
Rate of interest =  9%
Let the principal be P
We know that,
$S.I=\frac{P\times R\times T}{100}$
$45=\frac{P\times 9\times 1}{100}$
$\Rightarrow P=\frac{45\times 100}{9}$
$\therefore P=$  ₹ 500
The sum she borrowed is  ₹ 500.
The net amount she will pay at the end of one year = 500 + 45 =  ₹ 545.

Answer: Option A. ->
:
Formula: 1 Mark
Steps: 1 Mark
Each answer: 1 Mark
Given,
Harish borrowed ₹ 7500 from a bank.
a) The rate of interest is 5 %  p.a.
The principal amount, P = ₹ 7500
Rate of Interest, R = 5 %  p.a.
Time, T = 3 years
$S.I.=\frac{P\times R\times T}{100}$
$S.I.=\frac{7500\times 5\times 3}{100}$
S.I.= ₹ 1125
Amount = Principal + Interest
$\Rightarrow$ Amount = 7500 + 1125
Amount =  ₹ 8625
Hence, the total amount to be paid at the end of three years is  ₹ 8625
b) Now, Harish was able to pay only  ₹ 5625.
So, the remaining amount
=  ₹ (8625 - 5625) = ₹ 3000
The new principal amount =  ₹ 3000
The rate of interest is same = 5 % p.a.
The interest which he has to pay at the end of the fourth year
 = $\frac{5}{100}\times 3000$ =  ₹ 150
So, the amount which Harish has to pay at the end of the fourth year
= 3000 + 150 =  ₹ 3150
 

Answer: Option A. ->
:

Concept: 1 Mark
Steps: 1 Mark
Answer: 1 Mark Each
 Given that,
Cost price = ₹ 2500
Selling price = ₹ 3000
Selling price > Cost price $\Rightarrow$ Profit
$\therefore$ Profit = 3000 - 2500 = ₹ 500
$\text{Profit}\%=\frac{\text{Profit}}{CP}\times 100$
$\text{Profit}\%=\frac{500}{2500}\times 100$
$\text{Profit}\%=20\%$
Now it was sold for ₹ 2000.
The selling price, SP = ₹ 2000
SP<CP
Therefore it is a case of loss.
Loss = CP - SP = 2500 - 2000 = ₹ 500
So, the loss $\%$ is given by, 
Loss $\%$ = $\frac{500}{2500}\times 100$ = 20 $\%$