7th Grade > Mathematics
COMPARING QUANTITIES MCQs
:
B
Given that, 2 cm = 100 km
Therefore, 1 cm is equivalent to 50 km.
Actual dimensions of the room = (5×50) km × (4×50) km = 250 km × 200 km
:
A
For the given question, it is clear that marks scored by Ram is maximum.
Therefore, the percentage scored by him will be maximum.
Marks scored by Ram
= 90100
We know, percentages are numerators of fractions with denominator 100.
∴ Percentage of Ram's marks = 90%
:
C
Percentage marks scored in Aptitude
=4550×100= 90%
Percentage marks scored in General Mathematics
=4050×100=80%
Percentage marks scored in General Awareness
=3550×100=70%
Percentage marks scored in English
=4050×100=80%
:
Given that 88% of bronze is copper.
88gms of copper is present in 100gms bronze.
Therefore, in 200gms bronze;
weight of copper = 2 × 88 = 176gms
:
Percentage of students who like studying mathematics = no of students who like mathstotal no of students × 100 = 3040 x 100 = 75%
Amita has 12 marbles and Reeta has 8 marbles. Reeta says that she has x/y times the marbles that Amita has, where x and y are co-prime numbers.
Then x + y =
___
:
Since 8 = 23 × 12
Reeta has 23 times the marbles that Amita has
Therefore, x + y = 2 + 3 = 5
:
B
Profit = S.P - C.P = 18 - 12 = ₹ 6
Profit percentage
=ProfitC.P× 100
=612 × 100 = 50%
:
Simple Interest = PRT100
Principle, P = 4500.
Rate of Interest, R = x13.
Time, T = 2.
750 = 4500×R×2100
R = 253
R = 813
Hence, x = 8.
:
B
We can compare only two similar quantities.
:
Here, we have to check whether 25 is equal to 1015
If 25 = 1015; By cross-multiplication, we get 30 = 50. This is not true.
Therefore, ratios 2:5 and 10:15 not equivalent.