Clock(Reasoning Aptitude ) Questions and answers for exam Preparation

Reasoning Aptitude

CLOCK MCQs

Clocks

Total Questions : 146 | Page 3 of 15 pages

Question 21. At what angle the hands of a clock are inclined at 15 minutes past 5?

$\text"58"1°/2$
64°
$\text"67"1°/2$
$\text"72"1°/2$

Discuss Question

Answer: Option C. -> $\text"67"1°/2$
Answer: (c)
Angle traced by hour hand in 21/4 hrs =$ (360/12 × 21/4)^o = 157 1°/2$
Angle traced by min. Hand in 15 min = $(360/12 × 15)^o = 90°$
∴ Required angle = $(157 1°/2) - 90° = 67 1°/2$.

Question 22. Match List I with List II and select the correct answer using the codes given below the lists:
List I (Time)
List II (Angle between hour hand and minute hand of a clock)
A. 1:10 PM
20°
B. 2:15 PM
22$1/2$°
C. 8:40 PM
24°

25°

30°

A-4, B-2, C-1
A-4, B-3, C-2
A-5, B-2, C-1
A-4, B-3, C-2

Discuss Question

Answer: Option A. -> A-4, B-2, C-1
Answer: (a)
(A) Angle traced by hour hand in$ 7/6 hrs = (360/12 × 7/6)^o = 35°$
Angle traced by minute hand in $10 min = (360/60 × 10)^o = 60°$
∴ Required angle = (60° - 35°) = 25°
(B) Angle traced by hour hand in $9/4 hrs = (360/12 × 9/4)^o = 67 1°/2$
Angle traced by minute hand in $15 min = (360/60 × 15)^o = 90°$
∴ Required angle = $(90° - 67 1°/2) = 22 1°/2$
(C) Angle traced by hour hand in $26/3 hrs = (360/12 × 26/3)^o = 260°$
Angle traced by minute hand in $40 min = (360/60 × 40)^o$ = 240°
∴ Required angle = (260° - 240°) = 20°

Question 23. An accurate clock shows 8O' clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 2O, clock in the afternoon?

144°
150°
168°
180°

Discuss Question

Answer: Option D. -> 180°
Answer: (d)
Angle traced by the hour hand in $6 hours = (360/12 × 6)^o$ = 180°

Question 24. A clock gains 5 minutes in one hour. Therefore, the angle traversed by the minute hand in 1 hour is

360°
390°
390.5°
None of these

Discuss Question

Answer: Option B. -> 390°
Answer: (b)
Clearly, the minute hand traverses 65 minutes in 1 hour.
∴ Required angle = $(360/60 × 65)^o = 360°$

Question 25. The angle between the minute hand and the hour hand of a clock when the time is 4:20, is

0°
10°
5°
20°

Discuss Question

Answer: Option B. -> 10°
Answer: (b)
Angle traced by hour hand in $13/3 hrs = (360/12 × 13/3)^o= 130°$
Angle traced by min. hand in $20 min = (360/60 × 20)^o = 120°$
∴ Required angle = (130° - 120°) = 10°

Question 26. What will be the angle between the hands of clock at 9 : 30?

75°
90°
105°
120°

Discuss Question

Answer: Option C. -> 105°
Answer: (c)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 9 h 30 min
= [(9 × 60) + 30] × $1°/2$ = 570 × $1°/2$ = 285°
∴ angle traced by minute hand per minute = 6°
∴ angle traced by minute hand in 30 min = 30 × 6° = 180°
∴ required angle = (285° - 180°) = 105°

Question 27. What angle will be traced by the hands of a clock at 12 : 55?

$\text"87"1°/2$
$\text"67"1°/2$
$\text"57"1°/2$
$\text"27"1°/2$

Discuss Question

Answer: Option C. -> $\text"57"1°/2$
Answer: (c)
∴ Angle traced by hour hand per minute = $(1/2)^o$
&there4 Angle traced by hour hand in 12 h 55 min (i.e., at 0 : 55) = $55 × 1°/2 = 27 1°/2$
&there4 angle traced by minute hand per minute = 6°
Therefore traced by minute hand in 55 min = 55 × 6° = 330°
Therefore required angle = $360° - (330° - 27 1°/2) = 360° + 27 1°/2 - 330°$
$= 387 1°/2 - 330° = 57 1°/2$

Question 28. Find the angle between the two hands of clock at 4 : 10.

61°
68°
55°
65°

Discuss Question

Answer: Option D. -> 65°
Answer: (d)
∴ angle traced by hour hand per minute = $(1/2)^o$
Therefore angle traced by hour hand in 4 h 10 min = $[(4 × 60) + 10] × 1°/2 = 250 × 1°/2 = 125°$
∴ angle traced by minute hand per minute = 6°
∴ angle traced by minute hand in 10 min = 10 × 6° = 60°
∴ required angle = 125° - 60° = 65°

Question 29. What will be the measurement of the angle made by the hands of a clock when the time is 8 : 35?

32.4°
37.5°
45°
47.5°

Discuss Question

Answer: Option D. -> 47.5°
Answer: (d)
Angle traced by hour hand in 35 min after $8 = 35 × 1°/2 = 17.5°$
At 8 : 35, min hand is at 7, and angle between 8 and 7 = 30°
∴ required angle between two hand at 8 : 35 = 30° + 17.5° = 47.5°

Question 30. How much angular distance will be covered by the minute hand of a correct clock in a period of 2 h 20 min?

140°
840°
320°
520°

Discuss Question

Answer: Option B. -> 840°
Answer: (b)
Angle traced by minute hand per minute = 6°
Therefore angle traced by minute hand in 12 h 20 min = [(2 × 60) + 20] × 6°
= (120 + 20) × 6° = 140 × 6° = 840°