Reasoning Aptitude
CLOCK MCQs
Clocks
Total Questions : 146
| Page 2 of 15 pages
Answer: Option C. -> 1 a.m.
Answer: (c)
The watch loses 1/2 hour each hour.
So, it must have taken 8 hours to show 4 p.m. from 12 noon.
Thus, it stopped at 8 p.m. So, the correct time is 5 hours ahead of 8 p.m., i.e., 1 a.m.
Answer: (c)
The watch loses 1/2 hour each hour.
So, it must have taken 8 hours to show 4 p.m. from 12 noon.
Thus, it stopped at 8 p.m. So, the correct time is 5 hours ahead of 8 p.m., i.e., 1 a.m.
Answer: Option B. -> 4:10 a.m.
Answer: (b)
Duration from 12 noon to 4:00 a.m. = 16 hours.
Time gained in 24 hours = 15 min.
Time gained in 16 hours = (5/24 × 16) min = 10 min.
Answer: (b)
Duration from 12 noon to 4:00 a.m. = 16 hours.
Time gained in 24 hours = 15 min.
Time gained in 16 hours = (5/24 × 16) min = 10 min.
Answer: Option B. -> 5.00 a.m. on Wednesday
Answer: (b)
Time from 1 p.m. on Tuesday to 1 p.m. on Thursday = 48 hours.
So, the watch gains (1 + 2) min or 3 min in 48 hrs.
Now, 3 min are gained in 48 hrs. So, 1 min is gained in (48/3) = 16 hrs.
Answer: (b)
Time from 1 p.m. on Tuesday to 1 p.m. on Thursday = 48 hours.
So, the watch gains (1 + 2) min or 3 min in 48 hrs.
Now, 3 min are gained in 48 hrs. So, 1 min is gained in (48/3) = 16 hrs.
Answer: Option B. -> 14 hr 9 min 40 sec
Answer: (b)
Time lost in 6 $1/2$ hours = $(6 1/2 × 4) $sec = 26 sec.
Correct time after 6$ 1/2$ hours = 7 hr 40 min 6 sec + 6 hr 30 min = 14 hr 10 min 6 sec.
Time shown by the clock = 14 hr 10 min 6 sec - 26 sec = 14 hr 9 min 40 sec.
Answer: (b)
Time lost in 6 $1/2$ hours = $(6 1/2 × 4) $sec = 26 sec.
Correct time after 6$ 1/2$ hours = 7 hr 40 min 6 sec + 6 hr 30 min = 14 hr 10 min 6 sec.
Time shown by the clock = 14 hr 10 min 6 sec - 26 sec = 14 hr 9 min 40 sec.
Answer: Option B. -> 5.30 a.m.
Answer: (b)
Time lost I 1 hour = 5 min. Time lost in 6 hours = (5 × 6) min = 30 min.
After 6 hours, the correct time will be 6 a.m. and the clock will show 5.30 a.m.
Answer: (b)
Time lost I 1 hour = 5 min. Time lost in 6 hours = (5 × 6) min = 30 min.
After 6 hours, the correct time will be 6 a.m. and the clock will show 5.30 a.m.
Answer: Option A. -> 130°
Answer: (a)
∴ Angle traced by hour hand per minute =$(1/2)^o$
∴Angle traced by hour hand in 8h 20 min = ( 8 x 60 + 20) ×$ 1/2$ = 205°
Again, angle traced by minute hand per minute = 6°
∴ again traced by minute hand in 20 min = 20 × 6°
= 120°
Therefore required angle = (250° - 120°) = 130°
Answer: (a)
∴ Angle traced by hour hand per minute =$(1/2)^o$
∴Angle traced by hour hand in 8h 20 min = ( 8 x 60 + 20) ×$ 1/2$ = 205°
Again, angle traced by minute hand per minute = 6°
∴ again traced by minute hand in 20 min = 20 × 6°
= 120°
Therefore required angle = (250° - 120°) = 130°
Answer: Option D. -> 165°
Answer: (d)
∴ angle traced by hour hand per minute = $(1/2)^o$
∴ angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]^o$ = 510 × $(1/2)^o$ = 255°
∴ Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
∴ required angle = (255° - 180°) = 75°
Answer: (d)
∴ angle traced by hour hand per minute = $(1/2)^o$
∴ angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]^o$ = 510 × $(1/2)^o$ = 255°
∴ Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
∴ required angle = (255° - 180°) = 75°
Answer: Option B. -> $17 1°/2$
Answer: (b)
Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 7 h 35 min = [(7 × 60) + 35] × $1°/2$ = (420 + 35) × 1°/2 = 455 × $1°/2$ = 227 $1°/2$
∴ angle traced by minute hand per minute = 6°
Angle traced by minute hand in 35 min = 35 × 6° = 210°
∴ required angle = 227 1°/2 - 201° = 17$1°/2$
Answer: (b)
Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 7 h 35 min = [(7 × 60) + 35] × $1°/2$ = (420 + 35) × 1°/2 = 455 × $1°/2$ = 227 $1°/2$
∴ angle traced by minute hand per minute = 6°
Angle traced by minute hand in 35 min = 35 × 6° = 210°
∴ required angle = 227 1°/2 - 201° = 17$1°/2$
Answer: Option A. -> 180°
Answer: (a)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 1 h = 1°/2 × 60 = 30°
Time period between 8 O' clock to 2 O' clock = 6h
∴ angle traced by hour hand in 6h = 30° × 6 = 180°
Answer: (a)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 1 h = 1°/2 × 60 = 30°
Time period between 8 O' clock to 2 O' clock = 6h
∴ angle traced by hour hand in 6h = 30° × 6 = 180°
Answer: Option D. -> 75°
Answer: (d)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°$
Then, Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
Hence, Required angle = (255° - 180°) = 75°
Answer: (d)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°$
Then, Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
Hence, Required angle = (255° - 180°) = 75°
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