Quantitative Aptitude
CALENDAR MCQs
Total Questions : 273
| Page 25 of 28 pages
Answer: Option A. -> Sunday
Given that seventh day of a month is three days earlier than Friday
⇒ Seventh day is Tuesday
⇒ 14th is Tuesday
⇒ 19th is Sunday
Given that seventh day of a month is three days earlier than Friday
⇒ Seventh day is Tuesday
⇒ 14th is Tuesday
⇒ 19th is Sunday
Answer: Option D. -> Thursday
This is a leap year. So, none of the next 3 years will be leap years. Each year will give one odd day so the day of the week will be 3 odd days beyond Monday i.e. it will be Thursday.
This is a leap year. So, none of the next 3 years will be leap years. Each year will give one odd day so the day of the week will be 3 odd days beyond Monday i.e. it will be Thursday.
Answer: Option C. -> Wednesday
Given that 1st October is Sunday
Number of days in October = 31
31 days = 3 odd days
(As we can reduce multiples of 7 from odd days which will not change anything)
Hence 1st November = (Sunday + 3 odd days) = Wednesday
Given that 1st October is Sunday
Number of days in October = 31
31 days = 3 odd days
(As we can reduce multiples of 7 from odd days which will not change anything)
Hence 1st November = (Sunday + 3 odd days) = Wednesday
Answer: Option C. -> 26th May
1 - May - 2007
$$\eqalign{
& = \frac{{1 + 2 + 7 + 1 + 6}}{7} \cr
& = \frac{{17}}{7} \cr
& = 3 \cr
& = {\text{Tuesday}} \cr} $$
= May 1st → Tuesday + 5 days = Saturday = 5th may
5th may + 7 days = Saturday = 12th may
12th may + 7 days = Saturday = 19th may
19th may + 7 days = Saturday = 26th may
= Answer = 26th may
1 - May - 2007
$$\eqalign{
& = \frac{{1 + 2 + 7 + 1 + 6}}{7} \cr
& = \frac{{17}}{7} \cr
& = 3 \cr
& = {\text{Tuesday}} \cr} $$
= May 1st → Tuesday + 5 days = Saturday = 5th may
5th may + 7 days = Saturday = 12th may
12th may + 7 days = Saturday = 19th may
19th may + 7 days = Saturday = 26th may
= Answer = 26th may
Answer: Option D. -> 4
Odd days ⇒ The number of days more than complete number of weeks in the given period are odd days.
123 = 7 × 17 + 4 ⇒ 4 odd days.
Odd days ⇒ The number of days more than complete number of weeks in the given period are odd days.
123 = 7 × 17 + 4 ⇒ 4 odd days.
Answer: Option B. -> Friday
$$\frac{{126}}{7}$$ = 0
Each day of the week is repeated after 7 days.
So, after 126 days, it will be Friday.
After 126 days, it will be Friday
$$\frac{{126}}{7}$$ = 0
Each day of the week is repeated after 7 days.
So, after 126 days, it will be Friday.
After 126 days, it will be Friday
Answer: Option C. -> 4497 times
In 400 consecutive years there are 97 leap years. Hence, in 400 consecutive years February has the 29th day 97 times and the remaining eleven months have the 29th day 400 × 11 or 4400 times.
Thus the 29th day of the month occurs
= 4400 + 97
= 4497 times.
In 400 consecutive years there are 97 leap years. Hence, in 400 consecutive years February has the 29th day 97 times and the remaining eleven months have the 29th day 400 × 11 or 4400 times.
Thus the 29th day of the month occurs
= 4400 + 97
= 4497 times.
Answer: Option A. -> 5
Given that 25th August = Thursday
Hence 29th August = Monday
So 22nd,15th and 8th and 1st of August also will be Mondays
Number of Mondays in August = 5
Given that 25th August = Thursday
Hence 29th August = Monday
So 22nd,15th and 8th and 1st of August also will be Mondays
Number of Mondays in August = 5
Answer: Option C. -> Thursday
After every 400 years, the same day occurs. (Because a period of 400 years has 0 odd days)
Thus, 18th April 1603 is Thursday, After 400 years i.e., on 18th April 2003 has to be Thursday.
After every 400 years, the same day occurs. (Because a period of 400 years has 0 odd days)
Thus, 18th April 1603 is Thursday, After 400 years i.e., on 18th April 2003 has to be Thursday.
Answer: Option C. -> Monday
Formula : (Date + Month code + No.of years + No.of leap year + Century code)/7
$$\eqalign{
& = \frac{{21 + 6 + 87 + 21 + 0}}{7} \cr
& = \frac{{135}}{7} \cr
& = 2 \cr
& = {\text{Monday}} \cr} $$
Formula : (Date + Month code + No.of years + No.of leap year + Century code)/7
$$\eqalign{
& = \frac{{21 + 6 + 87 + 21 + 0}}{7} \cr
& = \frac{{135}}{7} \cr
& = 2 \cr
& = {\text{Monday}} \cr} $$
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