Quantitative Aptitude
BASIC MATHS MCQs
Total Questions : 233
| Page 6 of 24 pages
Answer: Option A. -> 12,342 litres.
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option C. -> 10
PART OF WORK COMPLETED BY A IN A DAY = 1/X PART OF WORK COMPLETED BY B IN A DAY
= 1/(X+5) (1/X)+(1/(X+5)) = 1/6 (2X+5)/(X²+5X) = 1/6 X²+5X = 6(2X+5) X²-7X-30=0 SOLVING, X=10
PART OF WORK COMPLETED BY A IN A DAY = 1/X PART OF WORK COMPLETED BY B IN A DAY
= 1/(X+5) (1/X)+(1/(X+5)) = 1/6 (2X+5)/(X²+5X) = 1/6 X²+5X = 6(2X+5) X²-7X-30=0 SOLVING, X=10
Answer: Option B. -> 25 days
WORK DONE BY P AND Q IN 1 DAY = 1/10
WORK DONE BY R IN 1 DAY = 1/50
WORK DONE BY P, Q AND R IN 1 DAY = 1/10 + 1/50 = 6/50
BUT WORK DONE BY P IN 1 DAY = WORK DONE BY Q AND R IN 1 DAY . HENCE THE ABOVE EQUATION CAN BE WRITTEN AS
WORK DONE BY P IN 1 DAY × 2 = 6/50
=> WORK DONE BY P IN 1 DAY = 3/50
=> WORK DONE BY Q AND R IN 1 DAY = 3/50
HENCE WORK DONE BY Q IN 1 DAY = 3/50 – 1/50 = 2/50 = 1/25
SO Q ALONE CAN DO THE WORK IN 25 DAYS
WORK DONE BY P AND Q IN 1 DAY = 1/10
WORK DONE BY R IN 1 DAY = 1/50
WORK DONE BY P, Q AND R IN 1 DAY = 1/10 + 1/50 = 6/50
BUT WORK DONE BY P IN 1 DAY = WORK DONE BY Q AND R IN 1 DAY . HENCE THE ABOVE EQUATION CAN BE WRITTEN AS
WORK DONE BY P IN 1 DAY × 2 = 6/50
=> WORK DONE BY P IN 1 DAY = 3/50
=> WORK DONE BY Q AND R IN 1 DAY = 3/50
HENCE WORK DONE BY Q IN 1 DAY = 3/50 – 1/50 = 2/50 = 1/25
SO Q ALONE CAN DO THE WORK IN 25 DAYS
Answer: Option A. -> 7
WORK DONE BY 10 MEN IN 1 DAY = 1/7
WORK DONE BY 1 MAN IN 1 DAY = (1/7)/10 = 1/70
WORK DONE BY 10 WOMEN IN 1 DAY = 1/14
WORK DONE BY 1 WOMAN IN 1 DAY = 1/140
WORK DONE BY 5 MEN AND 10 WOMEN IN 1 DAY = 5 × (1/70) + 10 × (1/140)
= 5/70 + 10/140 = 1/7
=> 5 MEN AND 10 WOMEN CAN COMPLETE THE WORK IN 7 DAYS
WORK DONE BY 10 MEN IN 1 DAY = 1/7
WORK DONE BY 1 MAN IN 1 DAY = (1/7)/10 = 1/70
WORK DONE BY 10 WOMEN IN 1 DAY = 1/14
WORK DONE BY 1 WOMAN IN 1 DAY = 1/140
WORK DONE BY 5 MEN AND 10 WOMEN IN 1 DAY = 5 × (1/70) + 10 × (1/140)
= 5/70 + 10/140 = 1/7
=> 5 MEN AND 10 WOMEN CAN COMPLETE THE WORK IN 7 DAYS
Answer: Option B. -> 8
LET WORK DONE BY P IN 1 DAY = P
WORK DONE BY Q IN 1 DAY =Q
WORK DONE BY R IN 1 DAY = R
P + Q = 1/8 —(1)
Q + R= 1/12 —(2)
P+ Q+ R = 1/6 —(3)
(3) – (2) => P = 1/6 – 1/12 = 1/12
(3) – (1) => R = 1/6 – 1/8 = 1/24
P + R = 1/12 + 1/24 = 3/24 = 1/8
=> P AND R WILL FINISH THE WORK IN 8 DAYS
LET WORK DONE BY P IN 1 DAY = P
WORK DONE BY Q IN 1 DAY =Q
WORK DONE BY R IN 1 DAY = R
P + Q = 1/8 —(1)
Q + R= 1/12 —(2)
P+ Q+ R = 1/6 —(3)
(3) – (2) => P = 1/6 – 1/12 = 1/12
(3) – (1) => R = 1/6 – 1/8 = 1/24
P + R = 1/12 + 1/24 = 3/24 = 1/8
=> P AND R WILL FINISH THE WORK IN 8 DAYS
Answer: Option D. -> 1800
NUMBER OF BOTTLES PRODUCED BY 1 MACHINE IN A MINUTE
= 270/6 NUMBER OF BOTTLES PRODUCED BY 10 MACHINES IN 4 MINUTES
= (270/6)*10*4 = 1800
NUMBER OF BOTTLES PRODUCED BY 1 MACHINE IN A MINUTE
= 270/6 NUMBER OF BOTTLES PRODUCED BY 10 MACHINES IN 4 MINUTES
= (270/6)*10*4 = 1800
Answer: Option A. -> 75/8 days
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option B. -> 5,760 litres
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option C. -> 16 min
IN THIS PROBLEM, RATE OF WATER PIPE (WASTE) IS MORE, THE TANK WILL BE EMPTIED WHEN THE PIPES ARE OPENED.
WORK DONE IN TOTAL EMPTYING IN 1 MIN.
=1/16−1/32=1/32
NOW, FULL TANK WILL BE EMPTIED BY THEM IN 32 MINUTES.
HALF FULL TANK WILL BE EMPTIED IN 16 MINUTES.
IN THIS PROBLEM, RATE OF WATER PIPE (WASTE) IS MORE, THE TANK WILL BE EMPTIED WHEN THE PIPES ARE OPENED.
WORK DONE IN TOTAL EMPTYING IN 1 MIN.
=1/16−1/32=1/32
NOW, FULL TANK WILL BE EMPTIED BY THEM IN 32 MINUTES.
HALF FULL TANK WILL BE EMPTIED IN 16 MINUTES.
Answer: Option B. -> 30 days
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!