Quantitative Aptitude
BASIC MATHS MCQs
Total Questions : 233
| Page 4 of 24 pages
Answer: Option B. -> Rs.70
AMOUNT EARNED BY P,Q AND R IN 1 DAY = 1620/9 = 180 —(1)
AMOUNT EARNED BY P AND R IN 1 DAY = 600/5 = 120 —(2)
AMOUNT EARNED BY Q AND R IN 1 DAY = 910/7 = 130 —(3)
(2)+(3)-(1) => AMOUNT EARNED BY P , Q AND 2R IN 1 DAY
– AMOUNT EARNED BY P,Q AND R IN 1 DAY = 120+130-180 = 70
=>AMOUNT EARNED BY R IN 1 DAY = 70
AMOUNT EARNED BY P,Q AND R IN 1 DAY = 1620/9 = 180 —(1)
AMOUNT EARNED BY P AND R IN 1 DAY = 600/5 = 120 —(2)
AMOUNT EARNED BY Q AND R IN 1 DAY = 910/7 = 130 —(3)
(2)+(3)-(1) => AMOUNT EARNED BY P , Q AND 2R IN 1 DAY
– AMOUNT EARNED BY P,Q AND R IN 1 DAY = 120+130-180 = 70
=>AMOUNT EARNED BY R IN 1 DAY = 70
Answer: Option B. -> 6
WORK DONE BY P IN 1 DAY = 1/18
WORK DONE BY Q IN 1 DAY = 1/15
WORK DONE BY Q IN 10 DAYS = 10/15 = 2/3
REMAINING WORK = 1 – 2/3 = 1/3
NUMBER OF DAYS IN WHICH P CAN FINISH THE REMAINING WORK = (1/3) / (1/18) = 6
WORK DONE BY P IN 1 DAY = 1/18
WORK DONE BY Q IN 1 DAY = 1/15
WORK DONE BY Q IN 10 DAYS = 10/15 = 2/3
REMAINING WORK = 1 – 2/3 = 1/3
NUMBER OF DAYS IN WHICH P CAN FINISH THE REMAINING WORK = (1/3) / (1/18) = 6
Answer: Option B. -> 16 days
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option A. -> 9(3/5) days
AMOUNT OF WORK P CAN DO IN 1 DAY = 1/16
AMOUNT OF WORK Q CAN DO IN 1 DAY = 1/12
AMOUNT OF WORK P, Q AND R CAN TOGETHER DO IN 1 DAY = 1/4
AMOUNT OF WORK R CAN DO IN 1 DAY = 1/4 – (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> HENCE R CAN DO THE JOB ON 48/5 DAYS = 9 (3/5) DAYS
AMOUNT OF WORK P CAN DO IN 1 DAY = 1/16
AMOUNT OF WORK Q CAN DO IN 1 DAY = 1/12
AMOUNT OF WORK P, Q AND R CAN TOGETHER DO IN 1 DAY = 1/4
AMOUNT OF WORK R CAN DO IN 1 DAY = 1/4 – (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> HENCE R CAN DO THE JOB ON 48/5 DAYS = 9 (3/5) DAYS
Answer: Option B. -> 10 days
WORK DONE BY P IN 1 DAY = 1/20
WORK DONE BY Q IN 1 DAY = 1/12
WORK DONE BY P IN 4 DAYS = 4 × (1/20) = 1/5
REMAINING WORK = 1 – 1/5 = 4/5
WORK DONE BY P AND Q IN 1 DAY = 1/20 + 1/12 = 8/60 = 2/15
NUMBER OF DAYS P AND Q TAKE TO COMPLETE THE REMAINING WORK = (4/5) / (2/15) = 6
TOTAL DAYS = 4 + 6 = 10
WORK DONE BY P IN 1 DAY = 1/20
WORK DONE BY Q IN 1 DAY = 1/12
WORK DONE BY P IN 4 DAYS = 4 × (1/20) = 1/5
REMAINING WORK = 1 – 1/5 = 4/5
WORK DONE BY P AND Q IN 1 DAY = 1/20 + 1/12 = 8/60 = 2/15
NUMBER OF DAYS P AND Q TAKE TO COMPLETE THE REMAINING WORK = (4/5) / (2/15) = 6
TOTAL DAYS = 4 + 6 = 10
Answer: Option A. -> 12 hrs
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option C. -> 16
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
NO EXPLANATION IS AVAILABLE FOR THIS QUESTION!
Answer: Option D. -> 136 days
TIME TAKEN IS INVERSELY PROPORTIONAL TO THEIR EFFICIENCY. SO, TIME TAKEN IS IN THE RATIO 8:5. TIME TAKEN BY RASHID TO FINISH THE WORK = 8X TIME TAKEN BY DANISH TO FINISH THE WORK = 5X 8X-5X=51 3X=51 X=17 8X=136
TIME TAKEN IS INVERSELY PROPORTIONAL TO THEIR EFFICIENCY. SO, TIME TAKEN IS IN THE RATIO 8:5. TIME TAKEN BY RASHID TO FINISH THE WORK = 8X TIME TAKEN BY DANISH TO FINISH THE WORK = 5X 8X-5X=51 3X=51 X=17 8X=136
Answer: Option A. -> 16
12 MEN WORK 8 HOURS FOR 10 DAYS X MEN WORK 12 HOURS FOR 5 DAYS X = (12*8*10)/(12*5) = 16 MEN
12 MEN WORK 8 HOURS FOR 10 DAYS X MEN WORK 12 HOURS FOR 5 DAYS X = (12*8*10)/(12*5) = 16 MEN
Answer: Option C. -> 8 hour 15 minutes
PAGES TYPED BY MANSOOR-UL-HAQUE IN 1 HOUR = 32/6 = 16/3
PAGES TYPED BY AAQIB IN 1 HOUR = 40/5 = 8
PAGES TYPED BY MANSOOR-UL-HAQUE AND AAQIB IN 1 HOUR = 16/3 + 8 = 40/3
TIME TAKEN TO TYPE 110 PAGES WHEN MANSOOR-UL-HAQUE AND AAQIB WORK TOGETHER = 110 × 3 /40 = 33/4
= 8 ¼ HOURS = 8 HOUR 15 MINUTES
PAGES TYPED BY MANSOOR-UL-HAQUE IN 1 HOUR = 32/6 = 16/3
PAGES TYPED BY AAQIB IN 1 HOUR = 40/5 = 8
PAGES TYPED BY MANSOOR-UL-HAQUE AND AAQIB IN 1 HOUR = 16/3 + 8 = 40/3
TIME TAKEN TO TYPE 110 PAGES WHEN MANSOOR-UL-HAQUE AND AAQIB WORK TOGETHER = 110 × 3 /40 = 33/4
= 8 ¼ HOURS = 8 HOUR 15 MINUTES