6th Grade > Mathematics
BASIC GEOMETRICAL IDEAS MCQs
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A circular sector or circle sector (symbol:⌔), is the portion of a disk enclosed by two radii and an arc, where the smaller area is known as the minor sector and the larger area is the major sector. In the diagram, θ is the central angle in radians, r is the radius of the circle, and L is the arc length of the minor sector.
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Line segment: 1 Mark
Ray: 1 Mark
Number of Lines segments: 1 Mark
In a line segment, the endpoints are fixed i.e. a line is contained between two points.
A ray is a portion of a line. It starts at one point and goes endlessly in one direction.
The line segments in the above figure are:
AB,AC,AD,AE,BC,BD,BE,CD,CE,DE.
Hence there 10 lines segments in the above figure.
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Each Point: 1 Mark
1. An infinite number of lines can pass through one given point.
2. Only one line can pass through two given points.
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Definition: 1 Mark
Solution: 1 Mark
A line segment is a piece, or part, of a line in geometry.
A line segment is represented by endpoints on each end of the line segment.
A line in geometry is represented by a line with arrows at each end.
A line segment and a line are different because a line goes on forever while a line segment has a distinct beginning and end.
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Each option: 1 Mark
The points that are lying inside the triangle are O, S
The points that are lying outside the triangle are T and N.
The only point that lies on the triangle is M.
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Explanation: 1 Mark
Solution: 1 Mark
Naming of Rays: 1 Mark
Common Ray: 1 Mark
In ∠ ABC and ∠ CBD, BC is a common arm. So, ∠ ABC and ∠ CBD form a linear pair.
Hence, ∠ ABC + ∠ CBD = ∠ ABD.
The various rays in the above figure are BA, BC, BD.
The two angles that share a common ray are ∠ABC and ∠CBD.
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Each option: 0.5 Marks
(a) ∠ ABD
(b) ∠ RTS
(c) ∠ ACD and ∠ ACB
(d) ∠ RTW and ∠ RTS
(e) ∠ AED, ∠ AEB, ∠ BEC and ∠ DEC
(f) ∠ AEC
(g) ∠ ACD
(h) ∠ AKO, ∠ AKP, ∠ BKO, ∠ BKP
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Each point: 1 Mark
(a) In line segments AE and EC, point E is a common point
So, AE + EC = AC
(b) In part (a) we have proved that:
AE + EC = AC
⇒ AC – EC = AE
(c) For line segments BE and ED, point E is a common point.
So, BE + ED = BD
⇒ BE – BE = ED
(d) Also, BE = BE + ED
⇒ BD – DE = BE
(∵ line segment ED = line segment DE)