Arithmetic Reasoning(Reasoning Aptitude ) Questions and answers for exam Preparation

Reasoning Aptitude

ARITHMETIC REASONING MCQs

Arithmetical Reasoning

Total Questions : 278 | Page 26 of 28 pages

Question 251. A bus starts from city X. The number of women in the bus is half of the number of men. In city Y, 10 men leave the bus and five women enter. Now, number of men and women is equal. In the beginning, how many passengers entered the bus ?

Discuss Question

Answer: Option D. -> 45
Originally, let number of women = x. Then, number of men = 2x.
So, in city Y, we have : (2x - 10) = (x + 5) or x - 15.
Therefore Total number of passengers in the beginning = (x + 2x) = 3x = 45.

Question 252. In a city, 40% of the adults are illiterate while 85% of the children are literate. If the ratio of the adults to that of the children is 2 : 3, then what percent of the population is literate ?

Discuss Question

Answer: Option D. -> 75%

Question 253. A farmer built a fence around his square plot. He used 27 fence poles on each side of the square. How many poles did he need altogether ?

100
104
108
None of these

Discuss Question

Answer: Option B. -> 104
Since each pole at the corner of the plot is common to its two sides, so we have :
Total number of poles needed = 27 x 4 - 4 = 108 - 4 = 104.

Question 254. A, B, C, D and E play a game of cards. A says to B, "If you give me 3 cards, you will have as many as I have at this moment while if D takes 5 cards from you, he will have as many as E has." A and C together have twice as many cards as E has. B and D together also have the same number of cards as A and C taken together. If together they have 150 cards, how many cards has C got ?

Discuss Question

Answer: Option A. -> 28
Clearly, we have :
A = B - 3 ...(i)
D + 5 = E ...(ii)
A+C = 2E ...(iii)
B + D = A+C = 2E ...(iv)
A+B + C + D + E=150 ...(v)
From (iii), (iv) and (v), we get: 5E = 150 or E = 30.
Putting E = 30 in (ii), we get: D = 25.
Putting E = 30 and D = 25 in (iv), we get: B = 35.
Putting B = 35 in (i), we get: A = 32.
Putting A = 32 and E = 30 in (iii), we get: C = 28.

Question 255. A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

9, 46
9, 50
10, 46
10, 50

Discuss Question

Answer: Option B. -> 9, 50
We have : A = 3B ...(i) and
C - 4 = 2 (A - 4) ...(ii)
Also, A + 4 = 31 or A= 31-4 = 27.
Putting A = 27 in (i), we get: B = 9.
Putting A = 27 in (ii), we get C = 50.

Question 256. A bird shooter was asked how many birds he had in the bag. He replied that there were all sparrows but six, all pigeons but six, and all ducks but six. How many birds he had in the bag in all?

Discuss Question

Answer: Option A. -> 9
There were all sparrows but six' means that six birds were not sparrows but only pigeons and ducks.
Similarly, number of sparrows + number of ducks = 6 and number of sparrows + number of pigeons = 6.
This is possible when there are 3 sparrows, 3 pigeons and 3 ducks i.e. 9 birds in all.

Question 257. Today is Varun's birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ?

20 years
22 years
25 years
27 years

Discuss Question

Answer: Option C. -> 25 years
Let Varan's age today = x years.
Then, Varan's age after 1 year = (x + 1) years.
Therefore x + 1 = 2 (x - 12) ⇔ x + 1 = 2x - 24 ⇔ x = 25.

Question 258. Mr. Johnson was to earn £ 300 and a free holiday for seven weeks' work. He worked for only 4 weeks and earned £ 30 and a free holiday. What was the value of the holiday?

£ 300
£ 330
£ 360
£ 420

Discuss Question

Answer: Option B. -> £ 330

Question 259. What is the smallest number of ducks that could swim in this formation - two ducks in front of a duck, two ducks behind a duck and a duck between two ducks ?

Discuss Question

Answer: Option A. -> 3
Clearly, the smallest such number is 3.
Three ducks can be arranged as shown above to satisfy all the three given conditions.

Question 260. On Children's Day, sweets were to be equally distributed among 175 children in a school. Actually on the Children's Day, 35 children were absent and therefore each child got 4 sweets extra. Total how many sweets were available for distribution ?