Arithmetic Reasoning(Reasoning Aptitude ) Questions and answers for exam Preparation

Reasoning Aptitude

ARITHMETIC REASONING MCQs

Arithmetical Reasoning

Total Questions : 278 | Page 27 of 28 pages

Question 261. Between two book-ends in your study are displayed your five favourite puzzle books. If you decide to arrange the five books in every possible combination and moved just one book every minute, how long would it take you ?

1 hour
2 hours
3 hours
4 hours

Discuss Question

Answer: Option B. -> 2 hours
Clearly, number of ways of arranging 5 books = 5 ! = 5 x 4 x 3 x 2 x 1 = 120.
So, total time taken = 120 minutes = 2 hours.

Question 262. A printer numbers the pages of a book starting with 1 and uses 3189 digits in all. How many pages does the book have ?

1000
1074
1075
1080

Discuss Question

Answer: Option B. -> 1074
No. of digits in 1-digit page nos. = 1x9 = 9.
No. of digits in 2-digit page nos. = 2 x 90 = 180.
No. of digits in 3-digit page nos. = 3 x 900 = 2700.
No. of digits in 4-digit page nos. = 3189 - (9 + 180 + 2700) = 3189 - 2889 = 300.
Therefore No. of pages with 4-digit page nos. = (300/4) = 75.
Hence, total number of pages = (999 + 75) = 1074.

Question 263. A placed three sheets with two carbons to get two extra copies of the original. Then he decided to get more carbon copies and folded the paper in such a way that the upper half of the sheets were on top of the lower half. Then he typed. How many carbon copies did he get?

Discuss Question

Answer: Option B. -> 2
Since the number of carbons is 2, only two copies can be obtained.

Question 264. The taxi charges in a city comprise of a fixed charge, together with the charge of the distance covered. For a journey of 16 km, the charges paid are Rs. 156 and for a journey of 24 km, the charges paid are Rs. 204. What will a person have to pay for travelling a distance of 30 km?

Rs. 236
Rs. 240
Rs. 248
Rs. 252

Discuss Question

Answer: Option B. -> Rs. 240
Let the fixed charge be Rs. x and variable charge be Rs.y per km. Then,
x + 16y = 156 ...(i) and
x + 24y = 204 ...(ii)
Solving (i) and (ii), we get: x = 60, y = 6.
Therefore Cost of travelling 30 km = 60 + 30 y = Rs. (60 + 30 x 6) = Rs. 240.

Question 265. If readymade shirts need alterations 2 out of 3 in sleeves, 3 out of 4 in collar and 4 out of 5 in the body, how many alterations will be required for 60 shirts ?

Discuss Question

Answer: Option C. -> 133

Question 266. At the end of a business conference the ten people present all shake hands with each other once. How many handshakes will there be altogether ?

Discuss Question

Answer: Option B. -> 45
Clearly, total number of handshakes = (9+ 8 + 7 + 6 + 5 + 4 + 3 + 2+1) = 45.

Question 267. A group of 1200 persons consisting of captains and soldiers is travelling in a train. For every 15 soldiers there is one captain. The number of captains in the group is

Discuss Question

Answer: Option C. -> 75
Clearly, out of every 16 persons, there is one captain. So, number of captains (1200/16) = 75.

Question 268. After distributing the sweets equally among 25 children, 8 sweets remain. Had the number of children been 28, 22 sweets would have been left after equal distribution. What was the total number of sweets ?

328
348
358
Data inadequate

Discuss Question

Answer: Option C. -> 358
Let the total number of sweets be (25x + 8).
Then, (25x + 8) - 22 is divisible by 28
⇔ (25x - 14) is divisible by 28 ⇔ 28x - (3x + 14) is divisible by 28
⇔ (3x + 14) is divisible by 28 ⇔ x = 14.
Therefore Total number of sweets = (25 x 14 + 8) = 358.

Question 269. In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?

20
25
30
Data inadequate
None of these

Discuss Question

Answer: Option C. -> 30
Let the number of boys and girls participating in sports be 3x and 2x respectively.
Then, 3x = 15 or x = 5.
So, number of girls participating in sports = 2x = 10.
Number of students not participating in sports = 60 - (15 + 10) = 35.
Let number of boys not participating in sports be y.
Then, number of girls not participating in sports = (35 -y).
Therefore (35 - y) = y + 5 ⇔ 2y ⇔ 30 ⇔ y = 15.
So, number of girls not participating in sports = (35 - 15) = 20.
Hence, total number of girls in the class = (10 + 20) = 30.

Question 270. Mac has £ 3 more than Ken, but then Ken wins on the horses and trebles his money, so that he now has £ 2 more than the original amount of money that the two boys had between them. How much money did Mac and Ken have between them before Ken's win ?

£ 9
£ 11
£ 13
£ 15

Discuss Question

Answer: Option C. -> £ 13
Let money with Ken = x. Then, money with Mac = x + £ 3.
Now, 3x = (x + x + £ 3) + £ 2 ⇔ x = £ 5.
Therefore Total money with Mac and Ken = 2x + £ 3 = £ 13.