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8th Grade > Mathematics

ALGEBRAIC EXPRESSIONS AND IDENTITIES MCQs

Total Questions : 88 | Page 6 of 9 pages
Question 51.


The area of a rectangle having length and width as 5xy and 9y respectively is 45xy.


  1.     True
  2.     False
  3.     5q2p
  4.     12pq2
 Discuss Question
Answer: Option B. -> False
:
B

Area of a rectangle = length × width


Area = 5xy×9y


        = 45xy2


Hence the given statement is false.


Question 52.


Which of the following are like terms to 9pq2?


  1.     8ab
  2.     5bc
  3.     5q2p
  4.     12pq2
 Discuss Question
Answer: Option C. -> 5q2p
:
C and D

Like terms are terms with the same variables raised to the same power. Coefficients of like terms need not be the same.
5q2p=5pq2.
Hence 5q2p and 12pq2 are both correct answers.


Question 53.


The product of (t+s2) and (t2s) is


  1.      t3+s2t2sts3
  2.      t3+s2t2sts2
  3.      t3+s2t22sts3
  4.      t3+t2sts3
 Discuss Question
Answer: Option A. ->  t3+s2t2sts3
:
A

(t+s2)(t2s)=[t(t2s)+s2(t2s)]
=t3ts+s2t2s3


=t3+s2t2sts3


Question 54.


Add the following:
a(a+b),b(b+c),c(a+c) and a2+b2+c2  [2 MARKS]


 Discuss Question
Answer: Option A. ->  t3+s2t2sts3
:

Concept: 1 Mark
Application: 1 Mark
a(a+b)+b(b+c)+c(a+c)+a2+b2+c2
a2+ab+b2+bc+c2+ca+a2+b2+c2
2a2+2b2+2c2+ab+bc+ca


Question 55.


Subtract (ap+bq-cr) from (a+b+c)(p+q+r) .  [1 MARK]


 Discuss Question
Answer: Option A. ->  t3+s2t2sts3
:
Concept: 1 Mark
(a + b + c)(p + q + r) - (ap + bq - cr)
= (ap + aq + ar + bp + bq + br + cp + cq + cr) - (ap + bq - cr)
Now,
= ap + aq + ar + bp + bq + br + cp + cq + cr - ap - bq + cr
= aq + ar + bp + br + cp + cq + 2cr
Question 56.


Using the identities of algebraic expressions , find 
(i) 1002×1003
(ii) 97×103.   [2 MARKS]


 Discuss Question
Answer: Option A. ->  t3+s2t2sts3
:

Application: 1 Mark each
(i)1002×1003
=(1000+2)(1000+3)10002+(2+3)1000+(3)(2)
=1000000+5000+6
=1005006
(ii)97×103
=(1003)(100+3)
=[(100)2(3)2]
=[100009]
=9991


Question 57.


Find the volume of rectangular boxes with the following length, breadth and height respectively
(i) (a2,a3,a4)
(ii) (x2y2,xz,z4)  
 [2 MARKS]


 Discuss Question
Answer: Option A. ->  t3+s2t2sts3
:

Concept: 1 Mark
Application: 1 Mark
(i) Volume = a2×a3×a4=a9
(ii) Volume = x2y2×xz×z4=x3y2z5                    
                    


Question 58.


Sandeep wants to buy 5 chocolates of Rs 10 each. He has to pay Rs 20 for parking also. If the price of chocolate is increased by Rs x, he decides to buy y less chocolates and he has to pay Rs z less for the parking. Write the arithmatic expression of the money spent by Sandeep.  [2 MARKS]


 Discuss Question
Answer: Option A. ->  t3+s2t2sts3
:

Concept: 1 Mark
Application: 1 Mark
Price of chocolate = (10 + x)


No. of chocolates = (5 – y)


Parking fees = (20 – z)


Total money spent =    (10 + x) (5 – y) + (20 – z)


Question 59.


Simplify the following:
(i) (1.5x4y)(1.5x+4y+3)
(ii) (x+y)(2x+y)+(x+2y)(xy)
(iii) (a2+5)(b3+3)+5  
[3 MARKS]


 Discuss Question
Answer: Option A. ->  t3+s2t2sts3
:

Application: 1 Mark each
(i) (1.5x4y)(1.5x+4y+3)
2.25x2+6xy+4.5x6xy16y212y
2.25x216y2+4.5x12y
(ii) (x+y)(2x+y)+(x+2y)(xy)
(2x2+xy+2xy+y2)+(x2+xy2y2)
3x2+4xyy2
(iii) (a2+5)(b3+3)+5
a2b3+3a2+5b3+15+5
a2b3+3a2+5b3+20


Question 60.


Using the identities of algebraic expressions, Find :
(i) 1022
(ii) 532
(iii) 10012  [3 MARKS]


 Discuss Question
Answer: Option A. ->  t3+s2t2sts3
:

Application: 1 Mark each
Using the identity :
(a+b)2=a2+2ab+b2
(i) (102)2
(100+2)2
(100)2+(2)2+2(100)(2)
10000+4+400
10404
(ii) (53)2
(50+3)2
(50)2+(3)2+2(50)(3)
2500+9+300
2809
(iii) (1001)2
(1000+1)2
(1000)2+(1)2+2(1000)(1)
1000000+1+2000
1002001


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