Question
Using the identities of algebraic expressions, Find :
(i) 1022
(ii) 532
(iii) 10012 [3 MARKS]
Answer: Option A
:
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Application: 1 Mark each
Using the identity :
(a+b)2=a2+2ab+b2
(i) (102)2
⇒(100+2)2
⇒(100)2+(2)2+2(100)(2)
⇒10000+4+400
⇒10404
(ii) (53)2
⇒(50+3)2
⇒(50)2+(3)2+2(50)(3)
⇒2500+9+300
⇒2809
(iii) (1001)2
⇒(1000+1)2
⇒(1000)2+(1)2+2(1000)(1)
⇒1000000+1+2000
⇒1002001
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