Question
I. 9a2 + 18a + 5 = 0, II. 2b2 + 13b + 20 = 0 to solve both the equations to find the values of a and b?
Answer: Option A
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I. 9a2 + 3a + 15a + 5 = 0
=>(3a + 5)(3a + 1) = 0 => a = -5/3, -1/3
II. 2b2 + 8b + 5b + 20 = 0
=>(2b + 5)(b + 4) = 0 => b = -5/2, -4
a is always more than b.
a > b.
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