Question
While measuring the acceleration due to gravity by a simple pendulum, a student makes a positive error of 1% in the length of the pendulum and a negative error of 3% in the value of time period. His percentage error in the measurement of g by the relation g=4π2(lT2) will be
Answer: Option C
:
C
Percentage error in g=(%errorinl)+2(%errorinT)=1%+2(3%)=7%
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:
C
Percentage error in g=(%errorinl)+2(%errorinT)=1%+2(3%)=7%
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