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Question
If radius of the sphere is (5.3 ± 0.1)cm. Then percentage error in its volume will be        
Options:
A .  3+6.01 ×1005.3
B .  13× 0.01 ×1005.3
C .  (3×0.15.3)×100
D .  0.15.3×100
Answer: Option C
:
C
Volume of sphere (v) = 43πγ3
Percentage error in volume =3 ×Δγγ× 100 = (3 ×0.15.3)× 100

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