Question
Answer: Option D
:
D
It is given that AB = AD and BC = CD.
Since, two pairs of adjacent sides are equal, the ABCD is a kite.
According to the properties of a kite:
AC⊥BD
[Diagonals of kite are perpendicular.]
In ΔABD,
∠ADB = ∠ABD [∵BA=DA and angles opposite to equal sidesare equal]
But, ∠DAB ≠ ∠DCB
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:
D
It is given that AB = AD and BC = CD.
Since, two pairs of adjacent sides are equal, the ABCD is a kite.
According to the properties of a kite:
AC⊥BD
[Diagonals of kite are perpendicular.]
In ΔABD,
∠ADB = ∠ABD [∵BA=DA and angles opposite to equal sidesare equal]
But, ∠DAB ≠ ∠DCB
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