Answer : Option D

Explanation :

Total number of outcomes possible when a die is rolled = 6 (∵ any one face out of the 6 faces)
Hence, Total number of outcomes possible when two dice are rolled, n(S) = 6 × 6 = 36
Prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29 ... etc
Let E = the event that the total is a prime number
= {(1,1), (1,2), (1,4), (1,6), (2,1), (2,3), (2,5), (3,2), (3,4),
(4,1), (4,3), (5,2), (5,6), (6,1), (6,5)}
Hence, n(E) = 15

$MF#%
\text{P(E) = }\dfrac{\text{n(E)}}{\text{n(S)}} = \dfrac{15}{36} = \dfrac{5}{12}$MF#%