Question
#include<stdio.h>
int main()
{
int i;
char a[] = "\0";
if(printf("%s", a))
printf("The string is not empty\n");
else
printf("The string is empty\n");
return 0;
}
What will be the output of the program ?
#include<stdio.h>
int main()
{
int i;
char a[] = "\0";
if(printf("%s", a))
printf("The string is not empty\n");
else
printf("The string is empty\n");
return 0;
}
Answer: Option B
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The function printf() returns the number of charecters printed on the console.
Step 1: char a[] = '�'; The variable a is declared as an array of characters and it initialized
with "�". It denotes that the string is empty.
Step 2: if(printf("%s", a)) The printf() statement does not print anything, so it returns '0'(zero).
Hence the if condition is failed.
In the else part it prints "The string is empty".
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