Question
#include<stdio.h>
int main()
{
printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));
return 0;
}
What will be the output of the program in 16-bit platform (Turbo C under DOS) ?
#include<stdio.h>
int main()
{
printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));
return 0;
}
Answer: Option B
Was this answer helpful ?
Step 1:
printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));
The sizeof function returns the size of the given expression.
sizeof(3.0f) is a floating point constant. The size of float is 4 bytes
sizeof('3') It converts '3' in to ASCII value.. The size of int is 2 bytes
sizeof(3.0) is a double constant. The size of double is 8 bytes
Hence the output of the program is 4,2,8
Note: The above program may produce different output in other platform due to the platform dependency of C compiler.
In Turbo C, 4 2 8. But in GCC, the output will be 4 4 8.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution